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I have a string "2500 - SomeValue". How can I remove everything before the 'S' in 'SomeValue'?

var x = "2500 - SomeValue";
var y = x.substring(x.lastIndexOf(" - "),
// this is where I'm stuck, I need the rest of the string starting from here. 

Thanks for any help.

~ck

I have a string "2500 - SomeValue". How can I remove everything before the 'S' in 'SomeValue'?

var x = "2500 - SomeValue";
var y = x.substring(x.lastIndexOf(" - "),
// this is where I'm stuck, I need the rest of the string starting from here. 

Thanks for any help.

~ck

• javascript
• string
• parsing
• substring

Share Improve this question Follow edited Aug 20, 2009 at 22:58 Joel 19.4k33 gold badges6767 silver badges8484 bronze badges asked Aug 20, 2009 at 22:49 HcabnettekHcabnettek 12.9k3838 gold badges129129 silver badges192192 bronze badges

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7 Answers 7

Sorted by: Reset to default 9

Add 3 (the length of " - ") to the last index and leave off the second parameter. The default when you pass one parameter to substring is the go to the end of the string

var y = x.substring(x.lastIndexOf(" - ") + 3);

That's just:

var y = x.substring(x.lastIndexOf(" - ") + 3);

When you omit the second parameter, it just gives you everything to the end of the string.

EDIT: Since you wanted everything from after the " - " I've added 3 to the starting point in order to skip those characters.

try

var y = x.split(" ",2);

then you'll have an array of substrings. The third one y[2] will be what you need.

var y = x.substring(0, x.lastIndexOf(' - ') + 3)

var y = x.slice(x.lastIndexOf(" - "), x.length - 1);

This will return the value as a string no matter that value is or how long it is and it has nothing to do with arrays.

x.substring(x.lastIndexOf(" - "),x.length-1); //corrected

var y = x.slice(x.lastIndexOf("-")+2);

Usually, we don't have space so we write +1 but in your case +2 works fine.

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