admin管理员组文章数量:1336117
What I'm trying to make is a check list for a lotto game, which is a sort of bingo for my family. I will first try to explain what the check list does and why, excuse my technical english, I'm dutch, so some words can be wrong :)
I have a list with a couple of people who play the lotto/bingo game. All players pick 10 numbers and once a week there is a draw of 6 numbers, I try to explain step by step what the code has to do.
1 - 10 people's numbers should be checked
2 - 6 numbers are added every week which should be pared with the numbers of the people.
3 - font should be colored green when there is a match.
4 - font should stay red when there is no match
Here is the code I have this far, a live version is at the link.
The code beneath works great, but the problem is that the code is designed to pare var A with var B, this is a bottleneck, because it's a 1 on 1 action. I can't add more people without adding a Draw day.
Now my question. What should be done to add more people (A1, A2, A3 etc etc.) without adding a draw date like B2.
I hope this is clear enough. :)
<script type = "text/javascript">
var a1 = ["2","3","8","12","23", "37", "41", "45", "48"]
var a2 = ["2","14","3","12","24", "37", "41", "46", "48"]
var b1 = ["2","5", "11","16","23","45", "46"];
var b2 = ["1","23", "11","14","23","42", "46"];
for (var i = 0; i< a1.length; i++)
{
for (var j = 0; j< b1.length; j++)
{
if (a1[i] == b1[j])
{
a1[i]= "g"+ a1[i];
}
}
}
for (var i = 0; i< a2.length; i++)
{
for (var j = 0; j< b2.length; j++)
{
if (a2[i] == b2[j]) {
a2[i]= "g"+ a2[i];
}
}
}
// john
document.write("<font color = '#FFFFFF'>" + "<b>" + "John    " + "</b>");
for (var i = 0; i< a1.length; i++)
{
if (a1[i].substr(0,1) == "g")
{
a1[i] = a1[i].substr(1,20);
document.write("<font color = '#00FF00'>", a1[i] + "    ");
}
else
{
document.write("<font color = '#FF0000'>", a1[i] + "    ");
}
}
// Michael
document.write("<br><br>");
document.write("<font color = '#FFFFFF'>" + "<b>" + "Michael    " + "</b>");
for (var i = 0; i< a2.length; i++)
{
if (a2[i].substr(0,1) == "g")
{
a2[i] = a2[i].substr(1,20);
// The Draw
document.write("<font color = '#00FF00'>", a2[i] + "    ");
}
else
{
document.write("<font color = '#FF0000'>", a2[i] + "    ");
}
}
document.write("<br><br>");
document.write("<br><br>");
document.write("<font color = '#FFFFFF'>" + "<b>" + "Draw day 1 " + "</b>");
document.write("<br>");
document.write("<font color = '#FFFFFF'>" + "<b>" + "Sat 08-08-2009 " + "</b>");
document.write("<br><br>");
for (var j = 0; j< b1.length; j++)
{
document.write("<font color = '#FFFFFF'>", b1[j] + "    ");
}
document.write("<br><br>");
document.write("<br><br>");
document.write("<font color = '#FFFFFF'>" + "<b>" + "Draw day 2 " + "</b>");
document.write("<br>");
document.write("<font color = '#FFFFFF'>" + "<b>" + "Sat 15-08-2009 " + "</b>");
document.write("<br><br>");
for (var j = 0; j< b2.length; j++)
{
document.write("<font color = '#FFFFFF'>", b2[j] + "    ");
}
</script>
What I'm trying to make is a check list for a lotto game, which is a sort of bingo for my family. I will first try to explain what the check list does and why, excuse my technical english, I'm dutch, so some words can be wrong :)
I have a list with a couple of people who play the lotto/bingo game. All players pick 10 numbers and once a week there is a draw of 6 numbers, I try to explain step by step what the code has to do.
1 - 10 people's numbers should be checked
2 - 6 numbers are added every week which should be pared with the numbers of the people.
3 - font should be colored green when there is a match.
4 - font should stay red when there is no match
Here is the code I have this far, a live version is at the link.
The code beneath works great, but the problem is that the code is designed to pare var A with var B, this is a bottleneck, because it's a 1 on 1 action. I can't add more people without adding a Draw day.
Now my question. What should be done to add more people (A1, A2, A3 etc etc.) without adding a draw date like B2.
I hope this is clear enough. :)
<script type = "text/javascript">
var a1 = ["2","3","8","12","23", "37", "41", "45", "48"]
var a2 = ["2","14","3","12","24", "37", "41", "46", "48"]
var b1 = ["2","5", "11","16","23","45", "46"];
var b2 = ["1","23", "11","14","23","42", "46"];
for (var i = 0; i< a1.length; i++)
{
for (var j = 0; j< b1.length; j++)
{
if (a1[i] == b1[j])
{
a1[i]= "g"+ a1[i];
}
}
}
for (var i = 0; i< a2.length; i++)
{
for (var j = 0; j< b2.length; j++)
{
if (a2[i] == b2[j]) {
a2[i]= "g"+ a2[i];
}
}
}
// john
document.write("<font color = '#FFFFFF'>" + "<b>" + "John    " + "</b>");
for (var i = 0; i< a1.length; i++)
{
if (a1[i].substr(0,1) == "g")
{
a1[i] = a1[i].substr(1,20);
document.write("<font color = '#00FF00'>", a1[i] + "    ");
}
else
{
document.write("<font color = '#FF0000'>", a1[i] + "    ");
}
}
// Michael
document.write("<br><br>");
document.write("<font color = '#FFFFFF'>" + "<b>" + "Michael    " + "</b>");
for (var i = 0; i< a2.length; i++)
{
if (a2[i].substr(0,1) == "g")
{
a2[i] = a2[i].substr(1,20);
// The Draw
document.write("<font color = '#00FF00'>", a2[i] + "    ");
}
else
{
document.write("<font color = '#FF0000'>", a2[i] + "    ");
}
}
document.write("<br><br>");
document.write("<br><br>");
document.write("<font color = '#FFFFFF'>" + "<b>" + "Draw day 1 " + "</b>");
document.write("<br>");
document.write("<font color = '#FFFFFF'>" + "<b>" + "Sat 08-08-2009 " + "</b>");
document.write("<br><br>");
for (var j = 0; j< b1.length; j++)
{
document.write("<font color = '#FFFFFF'>", b1[j] + "    ");
}
document.write("<br><br>");
document.write("<br><br>");
document.write("<font color = '#FFFFFF'>" + "<b>" + "Draw day 2 " + "</b>");
document.write("<br>");
document.write("<font color = '#FFFFFF'>" + "<b>" + "Sat 15-08-2009 " + "</b>");
document.write("<br><br>");
for (var j = 0; j< b2.length; j++)
{
document.write("<font color = '#FFFFFF'>", b2[j] + "    ");
}
</script>
Share
edited Aug 15, 2009 at 18:45
Mike Dinescu
55.8k17 gold badges122 silver badges153 bronze badges
asked Aug 15, 2009 at 18:38
ChrisChris
1,9396 gold badges35 silver badges60 bronze badges
13
- Do the "a"s hold players' picks and the "b"s hold the drawn numbers for the week? – outis Commented Aug 15, 2009 at 19:24
- @Chirs: I posted a few code snippets that I hope will help. Please let me know if you need clarity on any of them.. – Mike Dinescu Commented Aug 15, 2009 at 19:25
- @Chris: Are players allowed to change their picks? If so, do you want to keep a history of previous picks? – outis Commented Aug 15, 2009 at 20:12
- @Chris: is this a project for self-learning, homework or did you just want to run a bingo game? – outis Commented Aug 15, 2009 at 20:24
- 1 @ all, I'm a bit confused about how things work here, it's so different with what I normally see in help forums, I will read the FAQ first :) – Chris Commented Aug 15, 2009 at 21:23
4 Answers
Reset to default 4In addition to rewriting the code (refactoring) so the array parison into a function as Miky D did, you can make the parison more efficient by using an object to hold the winning numbers. Note that this code isn't the final version; there are further refinements.
var guesses = [["2","3","8","12","23", "37", "41", "45", "48"],
["2","14","3","12","24", "37", "41", "46", "48"]];
var draws = [ {2:1, 5:1, 11:1, 16:1, 23:1, 45:1, 46:1},
{1:1, 23:1, 11:1, 14:1, 23:1, 42:1, 46:1}];
function checkArray(guesses, draw) {
for (var i = 0; i< guesses.length; ++i) {
if (draw[guesses[i]]) {
guesses[i] = 'g' + guesses[i];
}
}
}
checkArray(guesses[0], draws[1]);
By turning the winning numbers into the indices rather than the values, you can get rid of a loop. Also, 'a' and 'b' aren't very descriptive names. Short names gain you nothing but obfuscation.
By marking successful and successful guesses differently (currently, you prepend 'g' to successes), you can also simplify the code to display the results. The <font>
tag has been deprecated for awhile, so this refinement uses <span>
s with a class that you can style.
function checkArray(guesses, draw) {
var results = {}
for (var i = 0; i< guesses.length; ++i) {
if (draw.picks[guesses[i]]) {
results[guesses[i]] = 'win';
} else {
results[guesses[i]] = 'loss';
}
}
return results;
}
...
document.write('<span class="name">John</span>');
var results = checkArray(guesses[0], draws[1]);
for (var p in results) {
document.write('<span class="'+results[i]+'">'+p+'</span>');
}
Since document.write
is also deprecated, I'll replace it with the modern equivalents, document.createElement
and Node.appendChild
. If you think the resulting code is too verbose, you can instead use innerHTML
, though its use is controversial. Since player names are closely tied to player picks, I'll also index the player picks by player name.
Put the following in a file named "lotto.js" in the same folder as the web page.
function Result(guesses) {
for (var i = 0; i< guesses.length; ++i) {
this[guesses[i]] = '';
}
}
function checkDraw(guesses, draw, results) {
for (var i = 0; i< guesses.length; ++i) {
if (draw.picks[guesses[i]]) {
results[guesses[i]] = 'picked';
}
}
return results;
}
function appendTo(elt, parent) {
if (parent) {
document.getElementById(parent).appendChild(elt);
} else {
document.body.appendChild(elt);
}
}
function printResults(name, results, parent) {
var resultElt = document.createElement('div');
resultElt.appendChild(document.createElement('span'));
resultElt.firstChild.appendChild(document.createTextNode(name));
resultElt.firstChild.className='name';
var picks = document.createElement('ol');
picks.className='picks';
for (var p in results) {
picks.appendChild(document.createElement('li'));
picks.lastChild.appendChild(document.createTextNode(p));
picks.lastChild.className = results[p];
}
resultElt.appendChild(picks);
appendTo(resultElt, parent);
}
function printResultsFor(name, draws, parent) {
var player = players[name];
var results = new Result(player);
for (var i=0; i<draws.length; ++i) {
checkDraw(player, draws[i], results);
}
printResults(name, results, parent);
}
function printDraw(which, draw, parent) {
var drawElt = document.createElement('div');
drawElt.className='draw';
drawElt.appendChild(document.createElement('h3'));
drawElt.lastChild.appendChild(document.createTextNode('Draw '+which));
drawElt.lastChild.className='drawNum';
drawElt.appendChild(document.createElement('div'));
drawElt.lastChild.className='date';
drawElt.lastChild.appendChild(document.createTextNode(draw.when));
var picks = document.createElement('ol');
picks.className='picks';
for (var p in draw.picks) {
picks.appendChild(document.createElement('li'));
picks.lastChild.appendChild(document.createTextNode(p));
}
drawElt.appendChild(picks);
appendTo(drawElt, parent);
}
Here's the corresponding HTML page:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<head>
<style type="text/css">
body {
font-family: Verdana, Arial, Helvetica, sans-serif;
color: white;
background-color: #333;
}
.picks, .picks * {
display: inline;
margin: 0;
padding: 0;
list-style-type: none;
}
.picks * {
margin: auto 0.25em;
}
#Results .picks * { color: red; }
.name, .picks .name {
color: white;
font-weight: bold;
margin-right: 0.5em;
}
#Results .picked { color: lime; }
.drawNum, #Draws H3 {
margin-bottom: 0;
}
</style>
<script type="text/javascript" src="lotto.js"></script>
</head>
<body>
<div id="Results"></div>
<div id="Draws"></div>
<script type="text/javascript">
var players = {John: [2, 3, 8, 12, 23, 37, 41, 45, 48],
Michael: [2, 14, 3, 12, 24, 37, 41, 46, 48]};
var draws = [ {when: 'Sat 08-08-2009',
picks:{2:1, 5:1, 11:1, 16:1, 23:1, 45:1, 46:1}},
{when: 'Sat 15-08-2009',
picks:{1:1, 23:1, 11:1, 14:1, 23:1, 42:1, 46:1}}];
for (name in players) {
printResultsFor(name, draws, 'Results');
}
for (var i=0; i<draws.length; ++i) {
printDraw(i+1, draws[i]);
}
</script>
</body>
</html>
You can refine the CSS to get the exact styling you want. The code could be further refactored to use OOP, which would simplify creating new players and draws, but it's more involved so I won't go in to it here.
Update: The above code was rewritten so that each player's guesses is pared to every draw. The live sample version of the code has been refactored almost beyond recognition to use OOP. It also uses features you probably haven't seen before, such as JS closures, higher order functions and CSS generated content and counters. It's longer and harder to understand but more flexible and a little easier to use.
you should use === as parison operator
For example let x = 5:
x == 8 // yield false
whereas:
x == "5" // yield **true**
=== is like saying "is exactly equal to" (by value and type)
x === 5 // yield true
x === "5" // yield false
I looks very nice thank you! I'm not sure if I did it correctly, but this is what I have. But it doesn't work in FireFox.
head section:
<script language="javascript">
// then call like this
checkValues(a1, b1);
var a = [["2","3","8","12","23", "37", "41", "45", "48"],
["2","14","3","12","24", "37", "41", "46", "48"]];
var b = [["2","5", "11","16","23","45", "46"],
["1","23", "11","14","23","42", "46"]];
var Players = ["John", "Michael"];
//Add a new player:
Players[2] = "Adam";
a[2] = ["9","3","7","12","23", "37", "40", "45", "24"];
function checkArray(myValues, winningValues)
{
for (var i = 0; i< myValues.length; i++)
{
for (var j = 0; j< winningValues.length; j++)
{
if (myValues[i] == winningValues[j])
{
myValues[i] = "g"+ myValues[i];
}
}
}
}
function displayNumbers(playerName, myNumbers)
{
document.write("<font color = '#FFFFFF'>" + "<b>" + playerName + "    " + "</b></font>");
for (var i = 0; i< myNumbers.length; i++)
{
if (myNumbers[i].substr(0,1) == "g")
{
myNumbers[i] = myNumbers[i].substr(1,20);
document.write("<font color = '#00FF00'>", myNumbers[i] + "</font>    ");
}
else
{
document.write("<font color = '#FF0000'>", myNumbers[i] + "</font>    ");
}
}
}
</script>
body section:
<body onload="checkValues(a1, b1);">
Here's a few things that I noticed:
- you could use array's of arrays to store the number picks and the winning numbers
- you could really create some functions to do the repeated work
- the HTML code that you render from your JS is not properly formed
Use functions to perform repeated code
function checkArray(myValues, winningValues)
{
for (var i = 0; i< myValues.length; i++)
{
for (var j = 0; j< winningValues.length; j++)
{
if (myValues[i] == winningValues[j])
{
myValues[i] = "g"+ myValues[i];
}
}
}
}
function displayNumbers(playerName, myNumbers)
{
document.write("<font color = '#FFFFFF'>" + "<b>" + playerName + "    " + "</b></font>");
for (var i = 0; i< myNumbers.length; i++)
{
if (myNumbers[i].substr(0,1) == "g")
{
myNumbers[i] = myNumbers[i].substr(1,20);
document.write("<font color = '#00FF00'>", myNumbers[i] + "</font>    ");
}
else
{
document.write("<font color = '#FF0000'>", myNumbers[i] + "</font>    ");
}
}
}
// then call like this
checkArray(a1, b1);
Use arrays of arrays to store your numbers and the winning numbers
var a = [["2","3","8","12","23", "37", "41", "45", "48"],
["2","14","3","12","24", "37", "41", "46", "48"]];
var b = [["2","5", "11","16","23","45", "46"],
["1","23", "11","14","23","42", "46"]];
var Players = ["John", "Michael"];
//Now you can do this:
// for each player
for(var k = 0; k < Players.length; k++)
{
// pare his numbers with each draw
for(var c = 0; c < b.length; c++)
{
checkArray(a[k], b[c]);
displayNumbers(Players[k], a[k]);
}
}
And adding a new player is as easy as
var a = [["2","3","8","12","23", "37", "41", "45", "48"],
["2","14","3","12","24", "37", "41", "46", "48"]];
var b = [["2","5", "11","16","23","45", "46"],
["1","23", "11","14","23","42", "46"]];
var Players = ["John", "Michael"];
//Add a new player:
Players[2] = "Adam";
a[2] = ["9","3","7","12","23", "37", "40", "45", "24"];
Of course you don't have to add people and draws at the same time..
本文标签: Compare array in javascriptStack Overflow
版权声明:本文标题:Compare array in javascript - Stack Overflow 内容由网友自发贡献,该文观点仅代表作者本人, 转载请联系作者并注明出处:http://www.betaflare.com/web/1742402692a2468203.html, 本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容,一经查实,本站将立刻删除。
发表评论