python - How to parameterize getfixturevalue, within a fixture? - Stack Overflow

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Is it possible to parameterize a fixture, which is used as a parameter in another fixture? I want to define a parent fixture, and have several variant fixtures which inherit from this parent fixture.

@pytest.fixture
def fixtureA(request):
    value = '1'
    if hasattr(request, 'param'):
        data = request.param
        if data.get('id'):
            value = data.get('id')
    return value

@pytest.fixture
@pytest.mark.parametrize("fixtureA", [{'id': '2'}], indirect=True)
def fixtureB(fixture_A):
    return fixtureA


def test_case(fixtureB):
    value = fixtureB
    assert value == '2'

From the example, fixtureB inherits fixtureA, and I want to be able to return the value of '2' while calling fixtureB in the testcase. When running the testcase, it is still returning the default value of '1'

Is it possible to parameterize a fixture, which is used as a parameter in another fixture? I want to define a parent fixture, and have several variant fixtures which inherit from this parent fixture.

@pytest.fixture
def fixtureA(request):
    value = '1'
    if hasattr(request, 'param'):
        data = request.param
        if data.get('id'):
            value = data.get('id')
    return value

@pytest.fixture
@pytest.mark.parametrize("fixtureA", [{'id': '2'}], indirect=True)
def fixtureB(fixture_A):
    return fixtureA


def test_case(fixtureB):
    value = fixtureB
    assert value == '2'

From the example, fixtureB inherits fixtureA, and I want to be able to return the value of '2' while calling fixtureB in the testcase. When running the testcase, it is still returning the default value of '1'

• python
• pytest

Share Improve this question Follow asked Nov 20, 2024 at 4:31 GeeGee 1122 bronze badges

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1 Answer 1

Sorted by: Reset to default 0

According to the pytest documentation about parametrization (1, 2, and 3), @pytest.mark.parametrize can only be used on test functions (or classes). Not on fixtures.

When you run your example, parametrization of fixtureB is ignored, and fixtureA is called without param (a simple pytest.set_trace() inside fixtureA can show you that).

You can set parameters on fixtures, but with the following syntax :

@pytest.fixture(params=["1", "2"])
def myfixture(request):
    return request.param

But that, of course, does not allow you to perform indirect parametrization.

You could move your parametrize to the test function, and call fixtureA in your test even if you don’t use its value directly.

import pytest

@pytest.fixture
def fixtureA(request):
    value = "1"
    if hasattr(request, "param"):
        data = request.param
        if data.get("id"):
            value = data.get("id")
    return value


@pytest.fixture
def fixtureB(fixtureA):
    return fixtureA


@pytest.mark.parametrize("fixtureA", [{"id": "2"}], indirect=True)
def test_case(fixtureB, fixtureA):
    value = fixtureB
    assert value == "2"

That way, fixtureA has a param and is returning the correct value, even when called from fixtureB (because a fixture can only have a single result for the whole test scope).

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