javascript - SlickGrid 2.0 can't change row background color in odd indexes - Stack Overflow

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I'm trying to change the background color using this code:

  data.getItemMetadata = function (index)
  {
       if (index === 5)
       {
           return  {cssClasses: "Unverified"};
       }      
   }

It works perfect as long as the index is even. but with odd indexes it has no effect on the background color (it has effect on the font style). I suspect it has something to do with the zebra effect? (I don't know how to disable that)

Thanks.

I'm trying to change the background color using this code:

  data.getItemMetadata = function (index)
  {
       if (index === 5)
       {
           return  {cssClasses: "Unverified"};
       }      
   }

It works perfect as long as the index is even. but with odd indexes it has no effect on the background color (it has effect on the font style). I suspect it has something to do with the zebra effect? (I don't know how to disable that)

Thanks.

• javascript
• slickgrid

Share Improve this question Follow asked Nov 12, 2012 at 13:29 Slime recipeSlime recipe 2,28333 gold badges3333 silver badges4949 bronze badges

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2 Answers 2

Sorted by: Reset to default 7

Your Unverified CSS class gets applied, but has no effect because it's specificity is lower than what is defined in slick-default-theme.css:

.slick-row.odd {
  background: #fafafa;
}

Notice that the selector uses a bination of two classes, which is more specific than your single Unverified class, hence it takes precedence.

You have two options:

1. Remove the existing rule.
2. Increase the specificity of your rule by adding .slick-row and placing it after the existing rule in the document, or by adding ! important at the end of your style declaration.

Neither of Tin's answers worked for me.

I was using:

.slick-row[row$="1"], .slick-row[row$="3"], .slick-row[row$="5"], .slick-row[row$="7"], .slick-row[row$="9"] {
  background: #E2E4FF;

}

But adding this to my CSS did:

.slick-row.odd {
  background: #E2E4FF;
}

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