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The lazy plugin works fine for the initially loaded elements but doesn't work for images loaded via AJAX despite having the code in done function of the AJAX call.
Here is my code for lazy loading images
jQuery(document).ready(function() {
jQuery("img.lazy").lazy({
effect: "fadeIn",
effectTime: 1000
});
});
Here is my AJAX call
$(document).ready(function() {
$('#loadmore-dj').on('click', function() {
$('#loadmore-dj').hide();
$('#loadmore-dj-gif').css( "display", "block");
$.ajax({
type: "GET",
url: "/loadmore/dj/",
data: {
'slug': $('.dj_slug').text().trim(),
'song_rank': $("#dj_song_list").find('.song_block').length
},
}).done(function (response) {
$(response).appendTo($('#dj_song_list')).hide().fadeIn(1000);
playOneAudio();
jQuery(document).ready(function() {
jQuery("img.lazy").lazy({
effect: "fadeIn",
effectTime: 1000
});
});
$('#loadmore-dj').show();
$('#loadmore-dj-gif').hide();
}).done(hideLoadMore);
});
});
The lazy plugin works fine for the initially loaded elements but doesn't work for images loaded via AJAX despite having the code in done function of the AJAX call.
Here is my code for lazy loading images
jQuery(document).ready(function() {
jQuery("img.lazy").lazy({
effect: "fadeIn",
effectTime: 1000
});
});
Here is my AJAX call
$(document).ready(function() {
$('#loadmore-dj').on('click', function() {
$('#loadmore-dj').hide();
$('#loadmore-dj-gif').css( "display", "block");
$.ajax({
type: "GET",
url: "/loadmore/dj/",
data: {
'slug': $('.dj_slug').text().trim(),
'song_rank': $("#dj_song_list").find('.song_block').length
},
}).done(function (response) {
$(response).appendTo($('#dj_song_list')).hide().fadeIn(1000);
playOneAudio();
jQuery(document).ready(function() {
jQuery("img.lazy").lazy({
effect: "fadeIn",
effectTime: 1000
});
});
$('#loadmore-dj').show();
$('#loadmore-dj-gif').hide();
}).done(hideLoadMore);
});
});
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edited Aug 14, 2014 at 5:05
Yin Yang
asked Aug 13, 2014 at 20:26
Yin YangYin Yang
1,8063 gold badges28 silver badges48 bronze badges
2
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Remove the inner
jQuery(document).ready(function() {...})
wrapper from your.done
callback; it's not needed. – Blazemonger Commented Aug 13, 2014 at 20:53 - Is this the plugin? jquery.eisbehr.de/lazy – Blazemonger Commented Aug 13, 2014 at 21:19
2 Answers
Reset to default 9The problem was the missing scroll-event on the AJAX load with lazy by default. Adding the config parameter bind: "event"
to lazy in my ajax function solved the issue.
jQuery("img.lazy").lazy({
effect: "fadeIn",
effectTime: 1000,
bind: "event"
});
Your .lazy
plugin is called before the fadeIn
is plete. Try this --
}).done(function (response) {
$(response).appendTo($('#dj_song_list')).hide().fadeIn(1000, function() {
playOneAudio();
jQuery("img.lazy").lazy({ // don't need document.ready twice
effect: "fadeIn",
effectTime: 1000
});
$('#loadmore-dj').show();
$('#loadmore-dj-gif').hide();
hideLoadMore(); // don't need two .done() callbacks.
});
});
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