admin管理员组文章数量:1334868
Here's a simple ajax call wrapped in a method.
MyNS.GetStringList = function (successCallback, failedCallback) {
var methodUrl = serverUrl + "/GetStringList";
$.ajax({
type: "GET",
contentType: "application/json; charset=utf-8",
dataType: "json",
url: methodUrl, // Location of the service
data: {}, //Data sent to server
beforeSend: function (XMLHttpRequest) {
//ensures the results will be returned as JSON.
XMLHttpRequest.setRequestHeader("Accept", "application/json");
},
success: successCallback,
error: failedCallback
});
}
Here's a method calling the above method.
function GoGetTheStringList() {
var stringList;
stringList = MyNS.GetStringList(function (data) { return data.d; }, function (XmlHttpRequest, textStatus, errorThrown) {
alert("error");
});
alert(reasonsDictionary); // THIS IS UNDEFINED!
}
What's the proper syntax to make the 1st method return the data.d object?
Thanks as always! Jon
Here's a simple ajax call wrapped in a method.
MyNS.GetStringList = function (successCallback, failedCallback) {
var methodUrl = serverUrl + "/GetStringList";
$.ajax({
type: "GET",
contentType: "application/json; charset=utf-8",
dataType: "json",
url: methodUrl, // Location of the service
data: {}, //Data sent to server
beforeSend: function (XMLHttpRequest) {
//ensures the results will be returned as JSON.
XMLHttpRequest.setRequestHeader("Accept", "application/json");
},
success: successCallback,
error: failedCallback
});
}
Here's a method calling the above method.
function GoGetTheStringList() {
var stringList;
stringList = MyNS.GetStringList(function (data) { return data.d; }, function (XmlHttpRequest, textStatus, errorThrown) {
alert("error");
});
alert(reasonsDictionary); // THIS IS UNDEFINED!
}
What's the proper syntax to make the 1st method return the data.d object?
Thanks as always! Jon
Share Improve this question asked Nov 21, 2011 at 14:03 user1231231412user1231231412 1,6592 gold badges26 silver badges42 bronze badges2 Answers
Reset to default 6It can't really. Ajax calls are asynchronous, which means the method will have returned before the success
callback is invoked.
EDIT / Correction: You may be able do it, but you will have to set the jQuery ajax async
option to false
, which means you will be performing a synchronous call, which means your whole app will be waiting for it to return. It's best if you pass a callback to your function to be called when success
is invoked.
In response to your edit: Yes, it will be undefined, because it is out of context. What you need to do is process your data from inside the callback, because at that point you will know you have it, and because you can't return data as a result of function A from function B. In your callback you should invoke a function to handle the data you got.
var latestData;
function getStuff(succeeded,failed) {...}
function gotStuff(dataWrapper) {
latestData = dataWrapper.d;
doThingsWithStuffData(dataWrapper.d);
}
getStuff(gotStuff, function () { ... });
You can use jQuery deffered as it is better suited for this purpose.
MyNS.GetStringList = function () {
var methodUrl = serverUrl + "/GetStringList";
return $.ajax({ // return here, this will returns a deffered object
type: "GET",
contentType: "application/json; charset=utf-8",
dataType: "json",
url: methodUrl, // Location of the service
data: {} //Data sent to server
});
}
You shouldn't need to do
beforeSend: function (XMLHttpRequest) {
//ensures the results will be returned as JSON.
XMLHttpRequest.setRequestHeader("Accept", "application/json");
},
That's what the dataType: 'json'
does, it gives jQuery a hint as to what to expect in the response from the server.
Then in your function
function GoGetTheStringList() {
var stringList;
$.when( MyNS.GetStringList() )
.done(function( data ){ console.log( data.d ); });
.fail(function( data ) { console.log('Request failed'); });
}
本文标签: javascript jquery ajax return object on successStack Overflow
版权声明:本文标题:javascript jquery ajax return object on success - Stack Overflow 内容由网友自发贡献,该文观点仅代表作者本人, 转载请联系作者并注明出处:http://www.betaflare.com/web/1742356238a2459468.html, 本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容,一经查实,本站将立刻删除。
发表评论