r - Variable names and Easystats reports - Stack Overflow

admin管理员组

文章数量:1333168

I am trying to fit a very simple logistic regression model on a data, and then try and get an easystats text report:

library(tidyverse)    
library(easystats)

    
    Data <- structure(list(`12_month_remission` = c(0, 1, 1, 0, 0, 0, 0, 
    0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 1, 0, 1, 1, 0, 0, 0, 0, 1, 0, 
    1, 1, 0, 1, 1, 0, 0, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 0, 0, 0, 0, 
    1), Sex = structure(c(2L, 1L, 1L, 2L, 2L, 2L, 1L, 2L, 2L, 1L, 
    1L, 1L, 2L, 1L, 2L, 1L, 2L, 2L, 2L, 1L, 2L, 1L, 1L, 1L, 2L, 2L, 
    1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 1L, 2L, 1L, 
    2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L), levels = c("Female", "Male"), class = "factor")), row.names = c(NA, 
    -50L), class = c("tbl_df", "tbl", "data.frame"))

glm(`12_month_remission` ~ Sex, family = "binomial", data = Data) %>% 
  report::report() 

And its coming up with:

Error in eval(predvars, data, env) : object '12_month_remission' not found Error: Unable to refit the model with standardized data.
Try instead to standardize the data (standardize(data)) and refit the model manually.

I know the model fit works, as if I just run the script without the report() I get an output. It doesnt make sense to Z-normalise data.. because there is no data that can be standardized? What am I missing?

I am trying to fit a very simple logistic regression model on a data, and then try and get an easystats text report:

library(tidyverse)    
library(easystats)

    
    Data <- structure(list(`12_month_remission` = c(0, 1, 1, 0, 0, 0, 0, 
    0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 1, 0, 1, 1, 0, 0, 0, 0, 1, 0, 
    1, 1, 0, 1, 1, 0, 0, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 0, 0, 0, 0, 
    1), Sex = structure(c(2L, 1L, 1L, 2L, 2L, 2L, 1L, 2L, 2L, 1L, 
    1L, 1L, 2L, 1L, 2L, 1L, 2L, 2L, 2L, 1L, 2L, 1L, 1L, 1L, 2L, 2L, 
    1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 1L, 2L, 1L, 
    2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L), levels = c("Female", "Male"), class = "factor")), row.names = c(NA, 
    -50L), class = c("tbl_df", "tbl", "data.frame"))

glm(`12_month_remission` ~ Sex, family = "binomial", data = Data) %>% 
  report::report() 

And its coming up with:

Error in eval(predvars, data, env) : object '12_month_remission' not found Error: Unable to refit the model with standardized data.
Try instead to standardize the data (standardize(data)) and refit the model manually.

I know the model fit works, as if I just run the script without the report() I get an output. It doesnt make sense to Z-normalise data.. because there is no data that can be standardized? What am I missing?

• r
• glm

Share Improve this question Follow edited Nov 20, 2024 at 20:42 zx8754 56.3k1212 gold badges125125 silver badges225225 bronze badges Recognized by R Language Collective asked Nov 20, 2024 at 15:25 Rover EyeRover Eye 24911 silver badge1313 bronze badges

Add a comment  | 

2 Answers 2

Sorted by: Reset to default 5

You're running into trouble because the name of your response variable isn't a legal R variable name. That's allowed (you just have to include it in ``, as you've already done), but in some cases (as you have found out) it causes problems downstream. Best practice would generally be to rename the variable to something not starting with a digit, e.g.

Data <- Data |> rename(remission = "12_month_remission")
m <- glm(remission ~ Sex, family = "binomial", data = Data)
report::report(m)

In slight contrast to @JilberUrbina's answer, which makes the same point, I would suggest doing this renaming as part of the initial 'data cleaning' section of your workflow where you do things like make sure that all variables have the required types (numeric vs categorical/factor), that factors have the right levels in a sensible order, etc., rather than doing it as part of a one-off pipe into glm() ...

It is about a matter of name in 12_month_remission. The easiest way to solve it is changing the name and it'll run

Data %>% 
  rename(remission_12_months = "12_month_remission") %>% 
  glm(remission_12_months ~ Sex, family = binomial, data = .) %>% 
  report::report() 

We fitted a logistic model (estimated using ML) to predict remission_12_months with Sex (formula: remission_12_months ~ Sex). The model's
explanatory power is weak (Tjur's R2 = 0.13). The model's intercept, corresponding to Sex = Female, is at 0.07 (95% CI [-0.69, 0.84], p =
0.847). Within this model:

  - The effect of Sex [Male] is statistically significant and negative (beta = -1.63, 95% CI [-3.06, -0.38], p = 0.015; Std. beta = -1.63, 95% CI
[-3.06, -0.38])

Standardized parameters were obtained by fitting the model on a standardized version of the dataset. 95% Confidence Intervals (CIs) and p-values
were computed using a Wald z-distribution approximation.

本文标签： rVariable names and Easystats reportsStack Overflow