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I'm looking for simple way to detect, if child element of parent with overflow:hidden is visible within parent (it's not hidden by overflow).

I found something like this:

/

but i wonder maybe there is simpler solution.

Thanks in advance!

I'm looking for simple way to detect, if child element of parent with overflow:hidden is visible within parent (it's not hidden by overflow).

I found something like this:

http://www.useallfive./thoughts/javascript-tool-detect-if-a-dom-element-is-truly-visible/

but i wonder maybe there is simpler solution.

Thanks in advance!

• javascript
• css
• overflow

Share Improve this question Follow asked Mar 16, 2017 at 18:54 Mathew KirmućMathew Kirmuć 10711 silver badge99 bronze badges 2

• 'simpler' is sort of vague. What do you not like about the solution you linked to? – jessegavin Commented Mar 16, 2017 at 19:00
• I believe this post will help you: stackoverflow./questions/17226000/… – iamjpg Commented Mar 16, 2017 at 19:17

Add a ment  | 

3 Answers 3

Sorted by: Reset to default 5

Assuming you want a vanilla js solution, try this:

function isVisible (parent, child) {
  return !(
    (child.offsetLeft - parent.offsetLeft > parent.offsetWidth) ||
    (child.offsetTop - parent.offsetTop > parent.offsetHeight)
  )
}

Basically "if the difference between the start of the parent element and the start of the child element is greater than the actual width or height of the parent, it's considered not visible"

Run the following snippet for an example:

var parent = document.getElementById('parent');

[].slice.call(document.querySelectorAll('.child')).forEach(function (child, i) {
  console.log(i + ' is visible?', isVisible(parent, child));
});

function isVisible(parent, child) {
  return !(
    (child.offsetLeft - parent.offsetLeft > parent.offsetWidth) ||
    (child.offsetTop - parent.offsetLeft > parent.offsetHeight)
  )
}

* {
  box-sizing: border-box;
}

#parent {
  width: 200px;
  height: 100px;
  white-space: nowrap;
  background: lightblue;
}

.child {
  display: inline-block;
  width: 75px;
  height: 100%;
  border: 1px solid green;
}

<div id="parent">
  <div class="child">0</div>
  <div class="child">1</div>
  <div class="child">2</div>
  <div class="child">3</div>
  <div class="child">4</div>
</div>

I had a similar requirement, but mine was a bit more plicated because the overflow: hidden element wasn't the first parent, it was like 5 or 6 elements away.

Just spend a whole day trying to do it with solutions from the internet(I've tried the repo you mentioned as well), but nothing worked.

So I've made this repo by myself (only JS, 2kb sized) https://github./LuizAsFight/is-element-visible.

It might help you, basically I just get the target element and climb the tree searching if any parent has a overflow:hidden, once I found it I get the parent's rect size, and check if the target element rect is inside the parent (visually, pixels)

for using it you just need to

import isVisible from 'is-element-visible';

const el = document.getElementById('id');
isVisible(el);

I hope it helps you, Best.

You can do the following things:

• check if the element has height and width that are bigger than 0px
• check if the element display CSS property is not "none", preferably "block"
• check if the element positioning is valid and if so, check if it´s "top" property is not bigger than the parent´s height
• Same thing for left - if it is not bigger than parent´s width

When checking "width", check offsetWidth and clientWidth, those will show actual numbers as displayed to the client.

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