javascript - In a recursive function, where to store results? - Stack Overflow

admin管理员组

文章数量:1332394

I'm currently trying to let JavaScript generate a truth table for a boolean function. Given a function, the code should just list all boolean binations possible, with the function output from each bination.

As for generating all binations, I put this together (simplified to the binations code only):

var table = [];
function binations(current) {
    var current = current || [];
    if(current.length === 3) {
        table.push(current);
    } else {
        var c = copy(current);
        c.push(true);
        binations(c);

        c = copy(current);
        c.push(false);
        binations(c);
    }
}

function copy(a) {
    var r = [];
    for(var i = 0; i < a.length; i++) r.push(a[i]);
    return r;
}

binations(); // now table consists of each pair of 3 boolean values

So basically when it has reached a bination (i.e. current.length === 3), it pushes a result record to table. I was wondering, however, whether this is the remended way of storing results of a recursive function.

I faced the remendation of using return inside the recursive function, but how would one implement such a thing - i.e., if binations in the end has to return an array containing all elements, how is it possible to do so? I could, of course, just use return table in the end, but I'm actually looking for a way to do this all inside the function, without an external variable like now.

So, how do I make binations return the results as an array without using an external variable?

I'm currently trying to let JavaScript generate a truth table for a boolean function. Given a function, the code should just list all boolean binations possible, with the function output from each bination.

As for generating all binations, I put this together (simplified to the binations code only):

var table = [];
function binations(current) {
    var current = current || [];
    if(current.length === 3) {
        table.push(current);
    } else {
        var c = copy(current);
        c.push(true);
        binations(c);

        c = copy(current);
        c.push(false);
        binations(c);
    }
}

function copy(a) {
    var r = [];
    for(var i = 0; i < a.length; i++) r.push(a[i]);
    return r;
}

binations(); // now table consists of each pair of 3 boolean values

So basically when it has reached a bination (i.e. current.length === 3), it pushes a result record to table. I was wondering, however, whether this is the remended way of storing results of a recursive function.

I faced the remendation of using return inside the recursive function, but how would one implement such a thing - i.e., if binations in the end has to return an array containing all elements, how is it possible to do so? I could, of course, just use return table in the end, but I'm actually looking for a way to do this all inside the function, without an external variable like now.

So, how do I make binations return the results as an array without using an external variable?

• javascript
• arrays
• recursion
• boolean
• return-value

Share Improve this question Follow edited Mar 21, 2011 at 14:42 pimvdb asked Mar 21, 2011 at 13:55 pimvdbpimvdb 155k8080 gold badges311311 silver badges356356 bronze badges

Add a ment  | 

4 Answers 4

Sorted by: Reset to default 4

Use Array.concat().

function binations(current) {
    var current = current || [];
    if(current.length === 3) {
        return [current];
    } else {
        return binations(current.concat(true)).concat(binations(current.concat(false)));
    }
}

var table = binations(); // now table consists of each pair of 3 boolean values

console.log(table);

Much more elegant, no?

Demo →

To avoid polluting the global space you could use a closure to contain your recursive function. There is an excellent writeup of this concept at http://drewwells/blog/2010/recursion-in-javascript/.

Your current solution seems fine to me. It might not be the most elegant, but it is simple and does the job (the only ugly bit is the hardcoded 3 - you should turn that into a parameter)

Your real question seems to be more language-agnostic than Javascript. If you want the function to return the binations, than you can prefectly do so, just clearly have in mind what your function should return and write the base and recursive cases:

function binations(domain, n){
    //returns a list of binations of length `n` with elements from `domain`
    if(n <= 0){
        return [[]]; //the empty bination is the only solution
    }else{
        var small_bs = binations(domain, n-1);
        var big_bs = [];
        for(var i=0; i<domain.length; i++){
            for(var j=0; j<small_bs.length; j++){
                big_bs.push(small_bs[j].concat(domain[i]))
            }
        }
        return big_bs;
     }
}

table = binations([true, false], 3);

var id = { "object": "page", "entry": [{ "id": "1588811284674233", "time": 1511177084837, "messaging": [{ "sender": { "id": "1393377930761248" }, "recipient": { "id": "1588811284674233" }, "timestamp": 1511177084553, "message": { "mid": "mid.$cAAX_9pLcfu1mCnGmiVf2Sxd2erI2", "seq": 1882, "text": "a" } }] }] };
function getKey(obj, data) {
      var data = data || [];
      if (obj) {
        var keys = Object.keys(obj);
        for (var pos in keys) {
          console.log();
          data.push(keys[pos]);
          if ((obj[keys[pos]].constructor === Array)) {
            for (var i = 0; i < obj[keys[pos]].length; i++) {
              getKey(obj[keys[pos]][i], data);
            }
          }
          else if (obj[keys[pos]].constructor === Object) {
            getKey(obj[keys[pos]], data);
          }
        }
        return data;
      }
    }

本文标签： javascriptIn a recursive functionwhere to store resultsStack Overflow