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How can I change this regular expression to remove everything from a string except alphabets and a '(single quote)?

pattern = /\b(ma?c)?([a-z]+)/ig;

1. this pattern removes unwanted spaces and capitalizes the first letter and turns the rest into lower case
2. By alphabets I mean English letters a-z.

How can I change this regular expression to remove everything from a string except alphabets and a '(single quote)?

pattern = /\b(ma?c)?([a-z]+)/ig;

1. this pattern removes unwanted spaces and capitalizes the first letter and turns the rest into lower case
2. By alphabets I mean English letters a-z.

• javascript
• regex

Share Improve this question Follow edited May 11, 2013 at 19:29 Sushan Ghimire asked Feb 19, 2012 at 14:16 Sushan GhimireSushan Ghimire 7,5671616 gold badges4141 silver badges6565 bronze badges 2

• 2 What’s an alphabet? Like the Latin alphabet, the Greek alphabet, the Cyrillic alphabet? Is this legacy 7-bit data, or is actually Unicode, which the web is now over 80% of? – tchrist Commented Feb 19, 2012 at 14:22
• 2 What is your current regexp about? More specifically, how's the \b(ma?c)? related to your need? – pimvdb Commented Feb 19, 2012 at 14:26

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1 Answer 1

Sorted by: Reset to default 8

To remove characters, you'd need to use something that actually does that, like the string replace function (which can accept a regular expression as the "from" parameter).

Then you're just dealing with a normal application of a character class, which in JavaScript (and most other regular expression variants) is described using [...], where ... is what should be in the class. You'd use the ^ at the beginning to invert the meaning of the class:

In your case, it might be:

str = str.replace(/[^A-Za-z']/g, "");

...which will replace except the English characters A-Z (ABCDEFGHIJKLMNOPQRSTUVWXYZ), a-z (abcdefghijklmnopqrstuvwxyz), and the single quote with nothing (e.g., remove it).

let str = "This is a test with the numbers 123 and a '.";

console.log("before:", str);
str = str.replace(/[^A-Za-z']/g, "");
console.log("after: ", str);

However, note that alphabetic characters not used in English will not be excepted, and there are a lot of those in the various languages used on the web (and even, perversely, in English, in "borrowed" words like "voilà" and "naïve").

You've said you're okay with just English A-Z, but for others ing to this: In environemnts supporting ES2018 and above's Unicode property matching, you could handle anything considered "alphabetic" by Unicode instead of just A-Z by using the \p{Alpha} property. The \p means "matching this Unicode property" (as usual, the lowercase version \p means "matching" and the uppercase version \P means "not matching") and the {Alpha} means "alphabetic":

str = str.replace(/[^\p{Alpha}']/gu, "");

(Note that, again, \p{Alpha} means "alphabetic" but because it's in a negated character class, we're excluding alphabetic characters.)

Note the u flag on that, to enable newer Unicode features. That handles the "voilà" and "naïve" examples too:

let str = "This is a test with the numbers 123 and a ' and voilà and naïve.";

console.log("before:", str);
str = str.replace(/[^\p{Alpha}']/gu, "");
console.log("after: ", str);

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