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I got requirement of the java-script Number formatting like below
I need one function its having 2 parameters like
var number = 1000;
var format = #,###.0; //or #,### ;
function ConvertNumber(number, format){
// this function need to return 1,000.0 if format is #,###.0
// this function need to return 1,000 if format is #,###
}
can anyone having this kind of function? your help is really appreciated thanks
I got requirement of the java-script Number formatting like below
I need one function its having 2 parameters like
var number = 1000;
var format = #,###.0; //or #,### ;
function ConvertNumber(number, format){
// this function need to return 1,000.0 if format is #,###.0
// this function need to return 1,000 if format is #,###
}
can anyone having this kind of function? your help is really appreciated thanks
Share Improve this question edited Nov 22, 2012 at 5:54 Ayush 42.5k51 gold badges168 silver badges241 bronze badges asked Nov 22, 2012 at 5:51 Rohan PatilRohan Patil 1,9631 gold badge23 silver badges36 bronze badges 8- And what your function "ConvertNumber" should do? – polin Commented Nov 22, 2012 at 5:52
- @polin that is what I wanted – Rohan Patil Commented Nov 22, 2012 at 5:54
- @Alex link is for java functions and not able to understand – Rohan Patil Commented Nov 22, 2012 at 5:56
-
1. What do you need to return if the value is 100 and the format is
#,###.0
? 2. Do you use only the given two formats? – prageeth Commented Nov 22, 2012 at 6:29 - what do you want in return for 10000000... is 10,000,000 or 10000,000...?? – Naz Commented Nov 22, 2012 at 6:34
3 Answers
Reset to default 3You can se the NumberFormatter plug-in from JQuery.
Here's an example of how you'd use this plugin.
$("#salary").blur(function(){
$(this).format({format:"#,###.00", locale:"de"});
});
check this function...
var number = 1000; // int or float or string
var format = '#,###.0'; // you can put any format that you want... only string
function ConvertNumber(number, format){
var tail=format.lastIndexOf('.');number=number.toString();
tail=tail>-1?format.substr(tail):'';
if(tail.length>0){if(tail.charAt(1)=='#'){
tail=number.substr(number.lastIndexOf('.'),tail.length);
}}
number=number.replace(/\..*|[^0-9]/g,'').split('');
format=format.replace(/\..*/g,'').split('');
for(var i=format.length-1;i>-1;i--){
if(format[i]=='#'){format[i]=number.pop()}
}
return number.join('')+format.join('')+tail;
}
// Examples
// ConvertNumber(1234,'#,###') === 1,234
// ConvertNumber(1234,'#,###.00') === 1,234.00
// ConvertNumber(1234,',###.00') === 1,234.00
// ConvertNumber(1234.4575,',###.##') === 1,234.45
// ConvertNumber(1234567890.4575,',###,###,###.##') === 1,234,567,890.45
// ConvertNumber(123.4575,',#,#.##') === 1,2,3.45
// ConvertNumber(123456.4575,'-#-#.##') === 1234-5-6.45
// ConvertNumber(1234567.4575,' ## ###.##') === 12 34 567.45
hope this function will be very helpful for you and them who have the same problem... best of luck...
Try this:
function ConvertNumber(number, decimals, dec_point, thousands_sep) {
// Strip all characters but numerical ones.
number = (number + '').replace(/[^0-9+\-Ee.]/g, '');
var n = !isFinite(+number) ? 0 : +number,
prec = !isFinite(+decimals) ? 0 : Math.abs(decimals),
sep = (typeof thousands_sep === 'undefined') ? ',' : thousands_sep,
dec = (typeof dec_point === 'undefined') ? '.' : dec_point,
s = '',
toFixedFix = function (n, prec) {
var k = Math.pow(10, prec);
return '' + Math.round(n * k) / k;
};
// Fix for IE parseFloat(0.55).toFixed(0) = 0;
s = (prec ? toFixedFix(n, prec) : '' + Math.round(n)).split('.');
if (s[0].length > 3) {
s[0] = s[0].replace(/\B(?=(?:\d{3})+(?!\d))/g, sep);
}
if ((s[1] || '').length < prec) {
s[1] = s[1] || '';
s[1] += new Array(prec - s[1].length + 1).join('0');
}
return s.join(dec);
}
Example:
example 1: ConvertNumber(1234.5678, 2, '.', ',');
returns 1: '1,234.57'
example 2: ConvertNumber(1000);
returns 2: '1,000'
example 3: ConvertNumber(1000.55, 1);
returns 3: '1,000.6'
example 4: ConvertNumber(67000, 5, ',', '.');
returns 4: '67.000,00000'
example 5: ConvertNumber('1.20', 4);
returns 5: '1.2000'
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