javascript - Regex - replace all odd numbered occurrences of a comma - Stack Overflow

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If I have a string formatted like this:

"name", "bob", "number", 16, "place", "somewhere" 

And I want, instead, to have a string like this:

"name": "bob", "number": 16, "place": "somewhere" 

Also, the test cases do have some examples of strings like this:

"name", "bob", "hello, world", true

That would need to be formatted like this:

"name" : "bob", "hello, world" : true

...with every odd ma being replaced by a colon (so long as that ma falls outside of quotes), how on Earth would I do that via regex?

I've found the following regex via Google: /(,)(?=(?:[^"]|"[^"]*")*$)/,':' , which matches the first ma instance. How do I alternate every other one from there on out?

Edit for more info:

What I'm trying to do is take this string where each value is delineated by a ma and format it like a JS object using .replace(). So, in this case, "name", "number" and "place" represent key values. They're not fixed, this is simply an example.

If I have a string formatted like this:

"name", "bob", "number", 16, "place", "somewhere" 

And I want, instead, to have a string like this:

"name": "bob", "number": 16, "place": "somewhere" 

Also, the test cases do have some examples of strings like this:

"name", "bob", "hello, world", true

That would need to be formatted like this:

"name" : "bob", "hello, world" : true

...with every odd ma being replaced by a colon (so long as that ma falls outside of quotes), how on Earth would I do that via regex?

I've found the following regex via Google: /(,)(?=(?:[^"]|"[^"]*")*$)/,':' , which matches the first ma instance. How do I alternate every other one from there on out?

Edit for more info:

What I'm trying to do is take this string where each value is delineated by a ma and format it like a JS object using .replace(). So, in this case, "name", "number" and "place" represent key values. They're not fixed, this is simply an example.

• javascript
• regex

Share Improve this question Follow edited Aug 22, 2014 at 3:54 radicalsauce asked Aug 22, 2014 at 3:21 radicalsauceradicalsauce 7166 bronze badges 10

• Can you use a custom callback for the replacement? – alex Commented Aug 22, 2014 at 3:23
• @alex - Could you clarify what you mean by that in this context? – radicalsauce Commented Aug 22, 2014 at 3:24
• Are the "name", "number", "place"... entries from a fixed set? – Freiheit Commented Aug 22, 2014 at 3:24
• What language are you using? – Andrew Whitaker Commented Aug 22, 2014 at 3:25
• Which language do you use and why not String operations? – thefourtheye Commented Aug 22, 2014 at 3:25

 |  Show 5 more ments

6 Answers 6

Sorted by: Reset to default 3

Regex:

,(.*?(?:,|$))

Replacement string:

:$1

DEMO

Example:

> '"name", "bob", "number", 16, "place", "somewhere" '.replace(/,(.*?(?:,|$))/g, ':$1');
'"name": "bob", "number": 16, "place": "somewhere" '

Update:

If the field names are ma seperated then you could try the below regex,

> '"name", "bob", "hello, world", true'.replace(/("(?:\S+?|\S+ \S+)"), ("[^"]*"|\S+)/g, '$1: $2');
'"name": "bob", "hello, world": true'

You can go with this Regular Expression that covers all matches together.

(?=(?:[^"]*"[^"]*")*[^"]*$)(,)(.*?,|)(?=.*?(?:,|$))

Replacement is: :$2

Live demo

substitude ([^,]+),([^,]+,) to \1:\2 apply it once, globally.

it has to be applied once. otherwise every but the last one , will bees :.

 "(.*?)(?<=\")(\s*)\,(\s*)(\S+)"

Replace by "\1\2:\3\4"

This works for all cases.

var str='"name", "bob", "hello, world", true';
str.replace(/("[^"]+"), ("[^"]+"|[^",]+)/g,"$1: $2");

The first part of the regex "[^"]+" captures the name under quotes: "name" or "hello, world".

The second part of the regex ("[^"]+"|[^",]+) captures either a name under quotes or a string without quote or ma: "bob" or true.

Ok here's an updated answer that (ab)uses JSON.parse and JSON.stringify:

function formatString(input) {
    var arr = JSON.parse('[' + input + ']'),
        result = '',
        i;

    for (i = 0; i < arr.length; i++) {
        result += JSON.stringify(arr[i]);

        if (i !== arr.length - 1) {
            if (i % 2 === 0) {
                result += ': ';
            } else {
                result += ', ';
            }
        }
    }

    return result;
}

Example: http://jsfiddle/w9eghqmy/1

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