admin管理员组

文章数量:1329861

Can you destructure the key, value, and index of an object in a forEach?

I understand destructuring key and value would look like: 

Object.entries(obj).forEach(([key, value]) => {
  ...
});

But I'm hoping to also destructure the index.

My attempt:

Object.entries(obj).forEach((entry, index) => {
    const [key, value] = entry;
    ...
});

But wasn't sure if there was a better way. I know this is a pretty basic question but thanks for the help!

Can you destructure the key, value, and index of an object in a forEach?

I understand destructuring key and value would look like: 

Object.entries(obj).forEach(([key, value]) => {
  ...
});

But I'm hoping to also destructure the index.

My attempt:

Object.entries(obj).forEach((entry, index) => {
    const [key, value] = entry;
    ...
});

But wasn't sure if there was a better way. I know this is a pretty basic question but thanks for the help!

  • javascript
  • object
  • ecmascript-6
  • destructuring
Share asked Feb 22, 2020 at 1:05 BWeb303BWeb303 3031 gold badge7 silver badges18 bronze badges
Add a ment  | 

1 Answer 1

Reset to default 10

Just list the index argument normally after destructuring the first argument:

Object.entries(obj).forEach(([key, value], index) => {


const obj = {
  foo: 'val'
};

Object.entries(obj).forEach(([key, value], index) => {
  console.log(key, value, index);
});

本文标签： javascriptDestructuring keyvalueand index of an object in es6Stack Overflow

版权声明：本文标题：javascript - Destructuring key, value, and index of an object in es6 - Stack Overflow 内容由网友自发贡献，该文观点仅代表作者本人， 转载请联系作者并注明出处：http://www.betaflare.com/web/1742265498a2443313.html， 本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容，一经查实，本站将立刻删除。