javascript - this.is(":checked") not working - Stack Overflow

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I'm using the following code to loop through all the checkboxes in my form. The boxes are gerenated dynamicaly from a php script so I won't know the names or the number of check boxes.

I need to find out which checkboxes have been ticked so I only pass those ones to the php script that handles the form.

 $("#panelform input:checkbox").each(function () {
    if(this.is(":checked")){
    fields = fields+"&"+this.name+"="+this.value;
}
});

When the script gets to the this.is(":checked") it errors but being jquery my console doesn't show me any error messages just stops.

if I alert or console.log "this" after the first line I get the form field so I know that that much works.

I'm using the following code to loop through all the checkboxes in my form. The boxes are gerenated dynamicaly from a php script so I won't know the names or the number of check boxes.

I need to find out which checkboxes have been ticked so I only pass those ones to the php script that handles the form.

 $("#panelform input:checkbox").each(function () {
    if(this.is(":checked")){
    fields = fields+"&"+this.name+"="+this.value;
}
});

When the script gets to the this.is(":checked") it errors but being jquery my console doesn't show me any error messages just stops.

if I alert or console.log "this" after the first line I get the form field so I know that that much works.

• javascript
• jquery

Share Follow asked Jan 14, 2013 at 15:49 flyersunflyersun 91733 gold badges1616 silver badges3535 bronze badges 2

• What do you mean "being jquery my console doesn't show me any error messages"? You should have seen something like Uncaught TypeError: Object #<HTMLInputElement> has no method 'is' – No Results Found Commented Jan 14, 2013 at 15:52
• JavaScript errors show up in the console even if you are using jQuery. The browser doesn't know/care what frameworks you use. – Álvaro González Commented Jan 14, 2013 at 15:54

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4 Answers 4

Sorted by: Reset to default 5

try with

 if($(this).is(":checked")){

since this is just a reference to the node in the DOM (and you need instead to use the jQuery wrapper to chain the method is().

Try this:

if( this.checked)

this is the plain DOM node, checked is its property to tell you if it's checked or not. Creating a whole new jQuery object just to see if a property is set is redundant.

In that contect, this refers to the DOM element, not the jQuery object - and DOM elements have no method is(). You can wrap it in a jQuery object if you want to use is method:

if($(this).is(":checked")){

or use the DOM Element's checked property:

if(this.checked){

$(this).is(':checked')

if you want to serialize your form try this

$('your-form-selector').serializeArray()

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