javascript - Filter relation query using bookshelf.js - Stack Overflow

admin管理员组

文章数量:1329924

How do I retrieve all records using through method but with a condition for the intermediate table, for ex: I want to retrieve all tracks for a channel where is_publish field from album (intermediate table)has value 1

my code so far looks as below:

new channelModel({'id': req.params.channel_id})
.fetch({withRelated: ['tracks']})
.then(function (channel) {
    if (channel) {
        res.json({error: false, status: 200, data: channel});
    } else {
        res.json({error: true, status: 404, data: 'channel does not exist'});
    }
})

With this code I retrieve all tracks.. And the channel model has a function defined as below:

tracks: function () {
    return this.hasMany('track').through('album');
}

my database looks smth like this:

channels: id,name,desc

albums:channel_id,name,descr,is_publish

tracks:album_id,name,descr

Any suggestion?

How do I retrieve all records using through method but with a condition for the intermediate table, for ex: I want to retrieve all tracks for a channel where is_publish field from album (intermediate table)has value 1

my code so far looks as below:

new channelModel({'id': req.params.channel_id})
.fetch({withRelated: ['tracks']})
.then(function (channel) {
    if (channel) {
        res.json({error: false, status: 200, data: channel});
    } else {
        res.json({error: true, status: 404, data: 'channel does not exist'});
    }
})

With this code I retrieve all tracks.. And the channel model has a function defined as below:

tracks: function () {
    return this.hasMany('track').through('album');
}

my database looks smth like this:

channels: id,name,desc

albums:channel_id,name,descr,is_publish

tracks:album_id,name,descr

Any suggestion?

• javascript
• bookshelf.js

Share Improve this question Follow edited Feb 25, 2015 at 1:39 Rhys van der Waerden 3,86722 gold badges2929 silver badges3232 bronze badges asked Feb 24, 2015 at 20:13 LulzimLulzim 54744 gold badges99 silver badges2222 bronze badges

Add a ment  | 

1 Answer 1

Sorted by: Reset to default 7

I haven't tested this, but I believe you can do the following:

ChannelModel = bookshelf.BaseModel.extend({
    tracks: function () {
        return this.hasMany('track').through('album');
    },
    publishedTracks: function () {
        return this.tracks().query('where', 'is_publish', true);
    },
    unpublishedTracks: function () {
        return this.tracks().query('where', 'is_publish', false);
    },
});

new ChannelModel({'id': req.params.channel_id})
.fetch({withRelated: ['pubishedTracks']})
.then(function (channel) {
    if (channel) {
        res.json({error: false, status: 200, data: channel.toJSON()});
    } else {
        res.json({error: true, status: 404, data: 'channel does not exist'});
    }
});

Alternatively, you may wish to do this:

new ChannelModel({'id': req.params.channel_id})
.fetch()
.tap(function (channel) {
    channel.tracks().query('where', 'is_publish', true).fetch()
})
.then(function(channel) {
    if (channel) {
        res.json({error: false, status: 200, data: channel.toJSON()});
    } else {
        res.json({error: true, status: 404, data: 'channel does not exist'});
    }
});

Also, while we're at it, I might point out require: true, which is a style I prefer for these situations.

new ChannelModel({'id': req.params.channel_id})
.fetch({ require: true })
.tap(function (channel) {
    channel.tracks().query('where', 'is_publish', true).fetch()
})
.then(function(channel) {
    res.json({error: false, status: 200, data: channel.toJSON()});
})
.catch(bookshelf.NotFoundError, function(error) {
    res.json({error: true, status: 404, data: 'channel does not exist'});
});

Also note that you were leaving off the call to .toJSON() in your response.

本文标签： javascriptFilter relation query using bookshelfjsStack Overflow