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I want to check the range of ip address in a regular expression , I was using this way and it's working so successfully

function validate_ip(ip)
{
       // See if x looks like an IP address using our "almost IP regex".
    var regex = /^(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})$/;
    var match = regex.exec(ip);
    if (!match) return false;
    // Additional code to check that the octets aren't greater than 255:
    for (var i = 1; i <= 4; ++i) {
        if (parseInt(match[i]) > 255) 
            return false;
    }
    return true;
}

now i want to perform checking of the range and the syntax in just regular expression can this be done ?

I want to check the range of ip address in a regular expression , I was using this way and it's working so successfully

function validate_ip(ip)
{
       // See if x looks like an IP address using our "almost IP regex".
    var regex = /^(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})$/;
    var match = regex.exec(ip);
    if (!match) return false;
    // Additional code to check that the octets aren't greater than 255:
    for (var i = 1; i <= 4; ++i) {
        if (parseInt(match[i]) > 255) 
            return false;
    }
    return true;
}

now i want to perform checking of the range and the syntax in just regular expression can this be done ?

• javascript
• regex
• ip

Share Improve this question Follow edited Jan 25, 2013 at 14:51 Alan Moore 75.3k1313 gold badges107107 silver badges161161 bronze badges asked Jan 24, 2013 at 14:35 SallySally 8722 silver badges1212 bronze badges 3

• 3 Yes, it could be done with regex - but why would you ever do that? – Bergi Commented Jan 24, 2013 at 14:37
• 2 Yes you could, but it would be far from pretty. – phant0m Commented Jan 24, 2013 at 14:38
• I know but I have to check url contains ip 192.168.0.137/sss – Sally Commented Jan 24, 2013 at 14:46

Add a ment  | 

3 Answers 3

Sorted by: Reset to default 5

The most straightforward approach is to look at the different cases:

25[0-5]|2[0-4]\d|1?\d\d?

This will match numbers between 0 and 255, disallowing prefixed zeroes such as: 055.

If you want to exclude zero:

25[0-5]|2[0-4]\d|1\d\d|[1-9]\d?

The regex for digits representing numbers from 1 to 255 would look like this:

/[1-9]|[1-9][0-9]|1[0-9][0-9]|2[0-4][0-9]|25[0-5]/
// next try, allowing 0:
/[1-9]?\d|1\d\d|2[0-4]\d|25[0-5]/

I think you will admit that using parseInt is much more readable, less errorprone and better maintainable.

It even could be shorter:

/^\d{1,3}(\.\d{1,3}){3}$/.test(ip) && ip.split(".").every(function(octet) {
    return parseInt(octet, 10) < 256;
});

(using ES5 every method, might need a shim for legacy browsers)

May late but, some one could try:

Example of valid IP address

115.42.150.37
192.168.0.1
110.234.52.124

Example of INVALID IP address

    210.110 – must have 4 octets
    255 – must have 4 octets
    y.y.y.y – only digit has allowed
    255.0.0.y – only digit has allowed
    666.10.10.20 – digit must between [0-255]
    4444.11.11.11 – digit must between [0-255]
    33.3333.33.3 – digit must between [0-255]

JavaScript code to validate an IP address

function ValidateIPaddress(ipaddress)   
{  
 if (/^(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$/.test(ipaddress))  
  {  
    return (true)  
  }  
alert("You have entered an invalid IP address!")  
return (false)  
}  

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