javascript - Node JS exec doesn't callback if exec an exe - Stack Overflow

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I have the following exec mand in a Node JS application that launches an EXE:

var exec = require('child_process').exec;

var theApp = 'HelloWorld';

var theCommand = 'C:/Program Files/' + theApp + '/dist/' + theApp + '-win32/' + theApp + '.exe';

exec(theCommand, function(error, stdout, stderr) {
    console.log('mand callback');
    console.log('stdout: ' + stdout);
    console.log('stderr: ' + stderr);
    if (error !== null) {
      console.log('exec error: ' + error);
    }
});

The EXE is launched fine, but none of the console logs are fired inside of the exec mand, so it's as though calling an exe doesn't cause a callback to be fired. If I exec another Node app, e.g. node app.js then it fires the callback! So it's because I'm calling an EXE to be opened!

How can I solve this?

I have the following exec mand in a Node JS application that launches an EXE:

var exec = require('child_process').exec;

var theApp = 'HelloWorld';

var theCommand = 'C:/Program Files/' + theApp + '/dist/' + theApp + '-win32/' + theApp + '.exe';

exec(theCommand, function(error, stdout, stderr) {
    console.log('mand callback');
    console.log('stdout: ' + stdout);
    console.log('stderr: ' + stderr);
    if (error !== null) {
      console.log('exec error: ' + error);
    }
});

The EXE is launched fine, but none of the console logs are fired inside of the exec mand, so it's as though calling an exe doesn't cause a callback to be fired. If I exec another Node app, e.g. node app.js then it fires the callback! So it's because I'm calling an EXE to be opened!

How can I solve this?

• javascript
• node.js

Share Improve this question Follow edited Jul 30, 2015 at 15:42 Cameron asked Jul 30, 2015 at 15:16 CameronCameron 28.9k102102 gold badges288288 silver badges490490 bronze badges 18

• The documentation states that the callback will only run after the process terminates. Can you confirm this is the case here? – blgt Commented Jul 30, 2015 at 15:20
• @blgt I'm not sure, is there a way to ensure the process terminates? – Cameron Commented Jul 30, 2015 at 15:21
• In fact! Wouldn't terminating the process mean that the EXE I've just called has been closed? Which isn't what I want. – Cameron Commented Jul 30, 2015 at 15:25
• @Cameron Well, the callback will only be executed once the process terminates which means that the application ("exe") has been closed. – Tobias Commented Jul 30, 2015 at 15:26
• How could I run the mand and get a callback ONCE the app has been executed? I don't have control of the other EXE so can't fire any events from that to say it has opened. Or is this not possible? – Cameron Commented Jul 30, 2015 at 15:36

 |  Show 13 more ments

1 Answer 1

Sorted by: Reset to default 9

When the program you are running starts up and does not terminate, you will not get any sort of callback or event until the program eventually exits. The system simply does not define any sort of event for that condition. A child process is either running or not. For any further detail about its condition, you are expected to municate with it in some way (stdin, stdout, stderr, connect socket to it, interrogate the process in the system, etc...)

Since the program can literally be doing anything, all you can know from the outside is whether it exited quickly with an error or exited quickly with no error or whether it appears to be still running. The return value from the exec() call contains a process ID so you can also query some info about that process ID if there's something specifically you want to know.

Here's an example of what you could do:

var exec = require('child_process').exec;

var theCommand = "notepad sample.txt";

function runit(cmd, timeout) {

    return new Promise(function(resolve, reject) {
        var ch = exec(theCommand, function(error, stdout, stderr) {
            if (error) {
                reject(error);
            } else {
                resolve("program exited without an error");
            }
        });
        setTimeout(function() {
            resolve("program still running");
        }, timeout);
    });
}

runit(theCommand, 1000).then(function(data) {
    console.log("success: ", data);
}, function(err) {
    console.log("fail: ", err);
});

It isn't clear to me which way you want it to act if the program you're running exits quickly, but without an error (the first call to resolve() in the code). You could change that to a reject() depending upon behavior what you want. I assumed that an exit without an error was not an error, but your situation might be different.

Note: if you aren't actually waiting for the pletion of the other program, you may not want to use .exec() since that is part of what it is built for. You may want to use one of the other child process creation methods.

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