admin管理员组文章数量:1332197
I have an image in my webpage i want when the user click on the image the current image also appear in the other div i have in my web page i am totally confuse please help me out here is my code.
<div id="img"><img src="download1.jpg"></div>
<div><img src="" class="img2"></div>
<img src="download1.jpg" alt="" class="imgs" id="the_id" width="180" height="60" />
<script type="text/javascript">
$(document).ready(function() {
$('.imgs').click(function(){
var idimg = $(this).attr('id');
var srcimg = $(this).attr('src');
alert('ID is: '+ idimg+ '\n SRC: '+ srcimg);
$(".img2").attr('src',srcimg);
});
});
</script>
I have an image in my webpage i want when the user click on the image the current image also appear in the other div i have in my web page i am totally confuse please help me out here is my code.
<div id="img"><img src="download1.jpg"></div>
<div><img src="" class="img2"></div>
<img src="download1.jpg" alt="" class="imgs" id="the_id" width="180" height="60" />
<script type="text/javascript">
$(document).ready(function() {
$('.imgs').click(function(){
var idimg = $(this).attr('id');
var srcimg = $(this).attr('src');
alert('ID is: '+ idimg+ '\n SRC: '+ srcimg);
$(".img2").attr('src',srcimg);
});
});
</script>
Share
Improve this question
asked Mar 26, 2014 at 8:27
VickyVicky
9822 gold badges11 silver badges30 bronze badges
1
- Working fine!! jsfiddle/kunknown/pb4US – Kiran Commented Mar 26, 2014 at 8:31
5 Answers
Reset to default 4Fiddle
Tried using a fiddle and it works, here is the code which I used.
HTML
<div id="img"><img src="https://encrypted-tbn2.gstatic./images?q=tbn:ANd9GcTgAVjAiDPV-oy-o9mvdHEsVoACUKJIuFcn08RJ5kRYINY4oqjPcA"></div>
<div><img src="" class="img2"></div>
<div>click me </div>
<img src="https://encrypted-tbn2.gstatic./images?q=tbn:ANd9GcTgAVjAiDPV-oy-o9mvdHEsVoACUKJIuFcn08RJ5kRYINY4oqjPcA" alt="" class="imgs" id="the_id" width="180" height="60" />
Jquery
$(document).ready(function() {
$('.imgs').click(function(){
var idimg = $(this).attr('id');
var srcimg = $(this).attr('src');
alert('ID is: '+ idimg+ '\n SRC: '+ srcimg);
$(".img2").attr('src',srcimg);
});
});
your code is perfect and will work check out you jquery library that is loaded correctly or not I have not seen any error in your code.
You can achieve this by setting the destination image's src to the same as the img
src in the clicked div. Try:
$('.source-img').on('click', function(){
var src = $(this).children('img').attr('src');
$('#destination').children('img').attr('src', src);
});
Check out this jsFiddle.
If you want the images to not have wrappers, then just change the jQuery targetting and leave out the .children(img)
part.
If you're looking for a better method, see this JSFiddle
It uses the clone function
$('.imgs').click(function(){
$(this).clone().appendTo('#LoadImageHere').attr('id', 'ClonedImage');
});
It means you don't have an image with an empty src attribute lying around, and you can add attributes to the cloned image as you wish (I added an ID in the example).
If you try width this code or here bination you can get very interesting result.Plz look" . Div element have in self img tag width source image,class "img2". Other image in gallery must have equal id, like is id "the_id". And if we clicking any picture that picture is show in space of div tag. How you can get bouncing effect picture must have equal size. I make bination two div tag where firs have class "img2", and second where is my picture distribute my pictures. With this first code on this page I make nice image gallery. Try and you self, this is not hard.
本文标签: javascripthow to show an image in another div after clicking the image in jqueryStack Overflow
版权声明:本文标题:javascript - how to show an image in another div after clicking the image in jquery - Stack Overflow 内容由网友自发贡献,该文观点仅代表作者本人, 转载请联系作者并注明出处:http://www.betaflare.com/web/1742236029a2438097.html, 本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容,一经查实,本站将立刻删除。
发表评论