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Im building a small space shooter game. I have how ever stubbed on a math problem when it e to the space physics.
Describing this with words is following: There is a max speed. So if you give full full speed you ship will move with this over the screen over and over again like in the old asteroids games. If then release the rocket boost you ship should be keep moving with that speed over the screen.
Then the tricky part where Im stuck right now.
If you rotate the ship ANY angle and gives boost again the ship should try to get to this direction and NEVER surpas the max speed when it es to how fast it is moving. so my question is. anyone have a good idea formula for this issue? feels like it has been done before if you know what to look for. :)
Ill add this small image to illustrate what is tried to be done with some vector calculations.
Red ring: Max speed
Green line: current ship direction.
Black line: direction(s) and how fast the ship is moveing in x and y.
Black ring: origin of movement.
Can illustrate it but hard to find a good math solution for this. :)
EDIT
This is the code Im using right now in every frame. It gives movement to the ship but does not give the force of movement the user has to counter-react with its rocket boosters to get the ship to stop or slow down. With this it stops the instant you release the accelerating speed for the ship.
//Calculates ship movement rules
var shipVelocityVec = GetVectorPosByAngle(shipMoveSpeed, shipRotationAngle);
var shipUnitVec =$V([Math.cos(shipRotationAngle),Math.sin(shipRotationAngle),0]);
var rawAccel = shipAccelSpeed / shipMass;
var scale = (shipUnitVec.dot(shipVelocityVec))/(shipTopSpeed * shipTopSpeed);
var v1 = shipUnitVec.subtract(shipVelocityVec.multiply(scale));
var finalAccelVec = v1.multiply(rawAccel);
console.log(finalAccelVec);
//move ship according to rules
var shipPosVector = $V([shipxPos, shipyPos, 0]);
var movementVector = shipPosVector.add(finalAccelVec);
shipxPos = movementVector.elements[0];
shipyPos = movementVector.elements[1];
To give the acceleration speed the user has to keep the button pressed. the instance the user releases the button the acceleration is set to zero and have to boost over again to give maximum acceleration throttle.
Solution found! Posted it here how it was done.
Im building a small space shooter game. I have how ever stubbed on a math problem when it e to the space physics.
Describing this with words is following: There is a max speed. So if you give full full speed you ship will move with this over the screen over and over again like in the old asteroids games. If then release the rocket boost you ship should be keep moving with that speed over the screen.
Then the tricky part where Im stuck right now.
If you rotate the ship ANY angle and gives boost again the ship should try to get to this direction and NEVER surpas the max speed when it es to how fast it is moving. so my question is. anyone have a good idea formula for this issue? feels like it has been done before if you know what to look for. :)
Ill add this small image to illustrate what is tried to be done with some vector calculations.
Red ring: Max speed
Green line: current ship direction.
Black line: direction(s) and how fast the ship is moveing in x and y.
Black ring: origin of movement.
Can illustrate it but hard to find a good math solution for this. :)
EDIT
This is the code Im using right now in every frame. It gives movement to the ship but does not give the force of movement the user has to counter-react with its rocket boosters to get the ship to stop or slow down. With this it stops the instant you release the accelerating speed for the ship.
//Calculates ship movement rules
var shipVelocityVec = GetVectorPosByAngle(shipMoveSpeed, shipRotationAngle);
var shipUnitVec =$V([Math.cos(shipRotationAngle),Math.sin(shipRotationAngle),0]);
var rawAccel = shipAccelSpeed / shipMass;
var scale = (shipUnitVec.dot(shipVelocityVec))/(shipTopSpeed * shipTopSpeed);
var v1 = shipUnitVec.subtract(shipVelocityVec.multiply(scale));
var finalAccelVec = v1.multiply(rawAccel);
console.log(finalAccelVec);
//move ship according to rules
var shipPosVector = $V([shipxPos, shipyPos, 0]);
var movementVector = shipPosVector.add(finalAccelVec);
shipxPos = movementVector.elements[0];
shipyPos = movementVector.elements[1];
To give the acceleration speed the user has to keep the button pressed. the instance the user releases the button the acceleration is set to zero and have to boost over again to give maximum acceleration throttle.
Solution found! Posted it here how it was done.
Share Improve this question edited Jul 25, 2018 at 9:22 PaulR 3,71716 silver badges25 bronze badges asked Feb 15, 2012 at 14:20 Jonas LindahlJonas Lindahl 80212 silver badges25 bronze badges 5- 2 I take it this is a 2d thing? Keep separate x and y velocity indicators. If you're thrusting at an angle, depose that angled thrust into x and y ponents, allowing you to adjust the ship's x/y velocity ponents separately. At each speed adjustment, check the ship's speed and stop adjusting if you've reached max. – Marc B Commented Feb 15, 2012 at 14:28
- Please correct me I'm misundestanding, but in image #3 isn't the bined vector for the speed larger than the red ring allows? – pimvdb Commented Feb 15, 2012 at 14:29
- No, as both x and y added togher thay equals the circels max movement. the green line could be longer. In #3 the green line should be the full length of the diameter of the circle. – Jonas Lindahl Commented Feb 15, 2012 at 14:33
- Separating X and Y movement is not a bad idea! – Jonas Lindahl Commented Feb 15, 2012 at 14:39
- +1 for making diagrams with your question – Arend Commented Feb 15, 2012 at 14:45
4 Answers
Reset to default 3You seem to be confusing something - there is no issue capping the velocity to a maximum speed, even when the acceleration is at a different angle, if you are using vectors correctly.
Your setup should look something like this:
- Your ship should have a position, a velocity, and an acceleration. Each of these can be represented as a 2D vector (with separate
x
andy
ponents). - Every frame, add the velocity to the position, and the acceleration to the velocity.
- Every frame, check that the speed does not exceed some maximum. If it does, cap the speed by normalizing the velocity vector and multiplying it by the max speed.
That's it! There are no special cases to consider - that's the magic of vector algebra!
@BlueRaja's solution should work, although you will get an abrupt change in behavior when you hit the max speed.
If you want a solution with no "seams", I believe you can do what you're looking for by adding the right kind of adjustment to the acceleration, as follows:
ship_unit_vec = [cos(ship_angle), sin(ship_angle)]
raw_accel = (engine_thrust / ship_mass)
scale = dot_product(ship_unit_vec, ship_velocity_vec) / max_speed^2
final_accel_vec = raw_accel * (ship_unit_vec - scale * ship_velocity_vec)
Notes:
- If
|ship_velocity_vec|<<max_speed
, thescale * ship_velocity_vec
ponent is negligable. - If
|ship_velocity_vec|==max_speed
, thescale * ship_velocity_vec
ponent cancels all additional acceleration in the "wrong" direction, and aids acceleration in the "right" direction. - I've never tried this out, so I don't know how it will feel to the player...
More generally, if there are more sources of acceleration than just the ship thrusters, you can add them all together (say, as raw_accel_vec
), and perform the above operation all at once:
scale_forall = dot_product(raw_accel_vec, ship_velocity_vec) / max_speed^2
final_accel_vec = raw_accel_vec - scale_forall * ship_velocity_vec
Rather than just imposing an ad hoc maximum speed, you could use some actual physics and impose a drag force. This would be an extra force acting on the spaceship, directed opposite to the velocity vector. For the magnitude of the drag force, it's simplest to just take it proportional to the velocity vector.
The overall effect is that the drag force increases as the spaceship moves faster, making it harder to accelerate in the direction of motion when the ship moves faster. It also makes acceleration easier when it is opposed to the direction of motion.
One point where this diverges from your description is that the spaceship won't continue at maximum speed forever, it will slow down. It won't, however, e to a halt, since the drag force drops as the ship slows down. That matches my memory of asteroids better than the ship continuing forever at constant velocity, but it has been quite a while since I've played.
I did it! Thank you for your help.
Finally found the solution. the problem was I was trying to modify the ships current movement when it es to speed and then of this calculate the "drag" forces that would be the product of this movement when the user tried to go another direction. The solution was like @BlueRaja and @Comingstorm mentioned. All forces should be added together when it es to the movement. This should be what then alter the ships position. Should not be added to the ships current movement. You might be able to effect a current movement to but then you have to do this differently. So I thought I share my solution for this how it looks.
This function is run each time the user accelerates the ship.
function CalcShipMovement() {
//Calculates ship movement rules
shipPosVector = $V([shipxPos, shipyPos, 0]);
var shipVelocityVec = GetVectorPosByAngle(shipAccelSpeed, shipRotationAngle);
var shipUnitVec = $V([Math.cos(shipRotationAngle), Math.sin(shipRotationAngle), 0]);
if(currentShipMoveVector != null && Get2DVectorLength(currentShipMoveVector) > 0) {
var nextMove = currentShipMoveVector.add(shipVelocityVec);
var nextSpeed = Get2DVectorLength(nextMove);
//check if topspeed of movement should be changed
if(nextSpeed > shipTopSpeed) {
var scale = nextSpeed / shipTopSpeed;
currentShipMoveVector = DevideVector(nextSpeed, scale);
} else {
currentShipMoveVector = currentShipMoveVector.add(shipVelocityVec);
}
}
if(currentShipMoveVector != null && Get2DVectorLength(currentShipMoveVector) == 0) {
currentShipMoveVector = currentShipMoveVector.add(shipVelocityVec);
}}
This code is run in every frame the graphics for the ship is generated to alter its position.
function SetShipMovement() {
if(currentShipMoveVector != null && Get2DVectorLength(currentShipMoveVector) > 0) {
shipMoveSpeed = Get2DVectorLength(currentShipMoveVector);
shipPosVector = shipPosVector.add(currentShipMoveVector);
shipxPos = shipPosVector.elements[0];
shipyPos = shipPosVector.elements[1];
//Makes the ship slow down if no acceleration is done for the ship
if(shipAccelSpeed == 0) {
currentShipMoveVector = currentShipMoveVector.subtract(DevideVector(currentShipMoveVector, 50));
}
} else {
currentShipMoveVector = $V([0, 0, 0]);
}}
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