Create javascript array using php to get images from directory - Stack Overflow

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I have a jquery function which relies on an array of images to create a fadeOut/In effect.

The line of code looks like this:

var images=new Array('/images/myImage1.jpg','/images/myImage2.jpg','/images/myImage3.jpg');

Currently I manually create this array but I would like to create it using php to grab the images in a directory on my server. I have found the following code which does this but I need to format so it looks like the javascript above.

<?php
$dir    = 'chamberImages/portfolio';
$files2 = scandir($dir, 1);
print_r($files2);
?>

I have a jquery function which relies on an array of images to create a fadeOut/In effect.

The line of code looks like this:

var images=new Array('/images/myImage1.jpg','/images/myImage2.jpg','/images/myImage3.jpg');

Currently I manually create this array but I would like to create it using php to grab the images in a directory on my server. I have found the following code which does this but I need to format so it looks like the javascript above.

<?php
$dir    = 'chamberImages/portfolio';
$files2 = scandir($dir, 1);
print_r($files2);
?>

• php
• javascript
• arrays
• directory

Share Improve this question Follow asked May 16, 2011 at 12:35 TomTom 13k5050 gold badges153153 silver badges247247 bronze badges 0

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3 Answers 3

Sorted by: Reset to default 6

You could just JSON encode the array that you have in $files2, removing the . and .. entries with array_slice:

var images = <?php echo json_encode(array_slice($files2, 2)); ?>;

You can use json:

json_encode($files2);

The result is a json formatted string that can be used as javascript code to create the array.

Use ajax. If you can't or do not want to do it, here is an inline PHP solution:

var images=new Array('<?php echo implode("', '", $files2) ?>');

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