javascript - How to find a middle point of a beizer curve? - Stack Overflow

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I want to make a 'named' bezier curve. I want it to be one-word named so I don't have to worry about word-wrap.

I make bezier curve via P5 bezier(sx,sy,c1x,c1y,c2x,c2y,ex,ey) function and I want a string to be shown in the middle of bezier curve. But I don't know how to find 'the middle' of curve.

For now my result looks like this (I don't know where to start picking up this problem, so I went with the easier way of just printing text on a start of curve):

But I want it to look like this:

This means that I need P1 and P2 coordinates:

Sorry for paint, but I don't have my code yet. As soon as I will have my hands on it I will add it here.

Here is code that draws a curve:

let
b = dest.inTriangle.middle, // destination triangle
g = this.outTriangle.p3,    // tip of out triangle
c = {x:b.x-g.x,y:b.y-g.y},  // distance between objects
r1 = {},                    // bezier point 1
r2 = {};                    // bezier point 2
if(c.x > 0){
    // b is on left
    r1 = {
        x: g.x + c.x/2,
        y: g.y
    };
    r2 = {
        x: b.x - c.x/2,
        y: b.y
    };
    }
else {
    // b is on right
    r1 = {
        x: g.x - c.x/2,
        y: g.y + c.y
    };
    r2 = {
        x: b.x + c.x/2,
        y: b.y - c.y
    };
}
noFill();
stroke(0);
bezier(
    g.x, g.y,
    r1.x, r1.y,
    r2.x, r2.y,
    b.x, b.y
);
noStroke();
fill(0);
text(this.name, g.x, (g.y-this.h/2))

I want to make a 'named' bezier curve. I want it to be one-word named so I don't have to worry about word-wrap.

I make bezier curve via P5 bezier(sx,sy,c1x,c1y,c2x,c2y,ex,ey) function and I want a string to be shown in the middle of bezier curve. But I don't know how to find 'the middle' of curve.

For now my result looks like this (I don't know where to start picking up this problem, so I went with the easier way of just printing text on a start of curve):

But I want it to look like this:

This means that I need P1 and P2 coordinates:

Sorry for paint, but I don't have my code yet. As soon as I will have my hands on it I will add it here.

Here is code that draws a curve:

let
b = dest.inTriangle.middle, // destination triangle
g = this.outTriangle.p3,    // tip of out triangle
c = {x:b.x-g.x,y:b.y-g.y},  // distance between objects
r1 = {},                    // bezier point 1
r2 = {};                    // bezier point 2
if(c.x > 0){
    // b is on left
    r1 = {
        x: g.x + c.x/2,
        y: g.y
    };
    r2 = {
        x: b.x - c.x/2,
        y: b.y
    };
    }
else {
    // b is on right
    r1 = {
        x: g.x - c.x/2,
        y: g.y + c.y
    };
    r2 = {
        x: b.x + c.x/2,
        y: b.y - c.y
    };
}
noFill();
stroke(0);
bezier(
    g.x, g.y,
    r1.x, r1.y,
    r2.x, r2.y,
    b.x, b.y
);
noStroke();
fill(0);
text(this.name, g.x, (g.y-this.h/2))

• javascript
• bezier
• p5.js

Share Improve this question Follow edited Jan 16, 2019 at 17:37 Kevin Workman 42.2k1212 gold badges7171 silver badges110110 bronze badges asked Jan 16, 2019 at 11:49 SkillGGSkillGG 68655 silver badges2020 bronze badges 4

• Will the curves always be symmetrical? or at least almost symmetrical? – Thomas Commented Jan 16, 2019 at 12:11
• Because I use symmetrical c1 and c2 I think, that curve will be always symmetrical. – SkillGG Commented Jan 16, 2019 at 12:14
• 2 If always symmetrical, then point at 1/2 will be the middle. If not, there is no simple way to pute the "middle" point, alas. – Jean-Baptiste Yunès Commented Jan 16, 2019 at 12:26
• Yes! I didn't think about it. I am kind of new to curves and it crushed me at first. Sorry – SkillGG Commented Jan 16, 2019 at 12:31

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2 Answers 2

Sorted by: Reset to default 6

You can use the bezierPoint() function that es with P5.js.

From the reference:

noFill();
var x1 = 85,
 x2 = 10,
 x3 = 90,
 x4 = 15;
var y1 = 20,
 y2 = 10,
 y3 = 90,
 y4 = 80;
bezier(x1, y1, x2, y2, x3, y3, x4, y4);
fill(255);
var steps = 10;
for (var i = 0; i <= steps; i++) {
  var t = i / steps;
  var x = bezierPoint(x1, x2, x3, x4, t);
  var y = bezierPoint(y1, y2, y3, y4, t);
  ellipse(x, y, 5, 5);
}

You'd probably want to use a value of 0.5 for t to get the midpoint.

The formula to translate the 4 points in a function over time is the following (image from wikipedia):

Since you want the middle, and t ranges from 0 to 1, you just have to set t = 1/2

So

B(1/2) = 1/8 P0 + 3/8 P1 + 3/8 P2 + 1/8 P3

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