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Hi everyone,
Actually, i got "c.replace is not a function" while i was trying to delete some DOM elements and..i don't understand.
i'd like to delete some
var liste=document.getElementById("tabs").getElementsByTagName("li");
for(i=0;i<liste.length;i++)
{
if(liste[i].id==2)
{
$("#tabs").detach(liste[i]);
}
}
I tried .detach and .remove but it's the same. My version of jQuery is 1.7.1.min.js.
Thanks for help.
Hi everyone,
Actually, i got "c.replace is not a function" while i was trying to delete some DOM elements and..i don't understand.
i'd like to delete some
var liste=document.getElementById("tabs").getElementsByTagName("li");
for(i=0;i<liste.length;i++)
{
if(liste[i].id==2)
{
$("#tabs").detach(liste[i]);
}
}
I tried .detach and .remove but it's the same. My version of jQuery is 1.7.1.min.js.
Thanks for help.
Share Improve this question asked Apr 20, 2012 at 13:01 Thomas SaldiThomas Saldi 911 gold badge2 silver badges9 bronze badges4 Answers
Reset to default 5order of iteration on a NodeLIst
Doing forward iteration of a NodeList that is being modified when you remove an element can be an issue. Iterate in reverse when removing elements from the DOM.
misuse of detach()
Also, the arguments to .detach()
do not perform a nested find, but rather act as a filter on the existing element(s) in the jQuery object, and should be passed a string. It seems that you actually want to detach the li
, which would mean that you'd need to call .detach()
on the li
itself...
var liste=document.getElementById("tabs").getElementsByTagName("li");
var i = liste.length
while(i--) {
if(liste[i].id==2) {
$(liste[i]).detach();
}
}
remove()
may be preferred
Keep in mind that if you use .detach()
, any jQuery data is retained. If you have no further use for the element, you should be using .remove()
instead.
// ...
$(liste[i]).remove(); // clean up all data
code reduction
Finally, since you're using jQuery, you could just do all this in the selector...
$('#tabs li[id=2]').remove(); // or .detach() if needed
valid id attributes
Keep these items in mind with respect to IDs...
- It's invalid to have duplicate IDs on a page
- It's invalid in HTML4 to have an ID that starts with a number
In the selector above, I used the attribute-equals filter, so it'll work, but you should really be using valid HTML to avoid problems elsewhere.
liste
is not (yet) a jQuery object. use $(liste[i])
or use
var liste= $('#tabs li');
Maybe I'm missing something, but is the id suppose to match the number 2.
var liste=document.getElementById("tabs").getElementsByTagName("li");
for(i=0;i<liste.length;i++) {
if(liste[i].id==2) {
$(liste[i]).detach();
}
}
Since you are already using jQuery, why not just do:
$("li", "#tabs").filter("#2").detach();
var two = document.getElementById('2');
two.parentNode.removeChild(two);
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