Execute PHP script on same page after selecting a dropdown list option using Ajax or JavaScript - Stack Overflow

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I am creating a MySQL query that will be execute when user select options from more a dropdown lists.

What I want is, on selecting a dropdown list option a query related to that option should be automatically executed using ajax/javascript on the same page. As I have the both html and php code on the same page.

Earlier I was using form submit options for dropdown list but as the number of dropdown option are more than five for filtering the result so queries became plicated to implement. That's why I want to refine result of each dropdown individually.

Any help is appreciated. Thanks in advance!

My HTML code for dropdown list is:

<p>
<label for="experience">Experience :</label>
<select id="experience" name="experience">
    <option value="" selected="selected">All</option>
    <option value="Fresher">Fresher</option>
    <option value="Experienced">Experienced</option>
</select>
</p>

PHP code for executing related queries is:

<?php
if (isset($_GET['exp'])) {

    switch ($_GET['exp']) {

        case 'Experienced':
        $query = "SELECT job_seekers.ID, job_seekers.Name, job_seekers.Skills, job_seekers.Experience FROM job_seekers where job_seekers.Experience!='Fresher'";
        break;

    case 'Fresher':
        $query = "SELECT job_seekers.ID, job_seekers.Name, job_seekers.Skills, job_seekers.Experience FROM job_seekers where job_seekers.Experience='Fresher'";
        break;

    default:
        $query = "SELECT job_seekers.ID, job_seekers.Name, job_seekers.Skills, job_seekers.Experience FROM job_seekers";

    }
}
$result = mysql_query($query) or die(mysql_error());

echo "<ul class=\"candidates\">";

while($row = mysql_fetch_row($result))
{
    echo "<li>";
    echo "<p> <b>ID:</b> <u>$row[0]</u> </p>";
    echo "<p> <b>Name :</b> $row[1] </p>";
    echo "<p> <b>Key Skills:</b> $row[2] </p>";
        echo "<p> <b>Experience:</b> $row[3] </p>";
    echo "</li>";
}

    echo "</ul>";               

?>

I am creating a MySQL query that will be execute when user select options from more a dropdown lists.

What I want is, on selecting a dropdown list option a query related to that option should be automatically executed using ajax/javascript on the same page. As I have the both html and php code on the same page.

Earlier I was using form submit options for dropdown list but as the number of dropdown option are more than five for filtering the result so queries became plicated to implement. That's why I want to refine result of each dropdown individually.

Any help is appreciated. Thanks in advance!

My HTML code for dropdown list is:

<p>
<label for="experience">Experience :</label>
<select id="experience" name="experience">
    <option value="" selected="selected">All</option>
    <option value="Fresher">Fresher</option>
    <option value="Experienced">Experienced</option>
</select>
</p>

PHP code for executing related queries is:

<?php
if (isset($_GET['exp'])) {

    switch ($_GET['exp']) {

        case 'Experienced':
        $query = "SELECT job_seekers.ID, job_seekers.Name, job_seekers.Skills, job_seekers.Experience FROM job_seekers where job_seekers.Experience!='Fresher'";
        break;

    case 'Fresher':
        $query = "SELECT job_seekers.ID, job_seekers.Name, job_seekers.Skills, job_seekers.Experience FROM job_seekers where job_seekers.Experience='Fresher'";
        break;

    default:
        $query = "SELECT job_seekers.ID, job_seekers.Name, job_seekers.Skills, job_seekers.Experience FROM job_seekers";

    }
}
$result = mysql_query($query) or die(mysql_error());

echo "<ul class=\"candidates\">";

while($row = mysql_fetch_row($result))
{
    echo "<li>";
    echo "<p> <b>ID:</b> <u>$row[0]</u> </p>";
    echo "<p> <b>Name :</b> $row[1] </p>";
    echo "<p> <b>Key Skills:</b> $row[2] </p>";
        echo "<p> <b>Experience:</b> $row[3] </p>";
    echo "</li>";
}

    echo "</ul>";               

?>

• php
• javascript
• mysql
• html
• ajax

Share Improve this question Follow edited Aug 31, 2012 at 7:33 h2ooooooo 39.6k88 gold badges7070 silver badges106106 bronze badges asked Aug 31, 2012 at 7:18 Yogesh RawalYogesh Rawal 10533 gold badges33 silver badges1313 bronze badges

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3 Answers 3

Sorted by: Reset to default 4

When you want to AJAX call a php script, you should you $.ajax provided by Jquery

http://api.jquery.

so you can use it like so:

$.ajax({
    url: 'ajax.php',
    data: {
        //put parameters here such as which dropdown you are using
    },
    success: function(response) {
        //javascript and jquery code to edit your lists goes in here.
        //use response to refer to what was echoed in your php script
    }
});

this way, you will have dynamic dropdowns and the refined results you want

<?php
if (isset($_GET['experience'])) {

    echo $_GET['experience'];
        /* do mysql operations and echo the result here */
    exit;
}
?>
<!DOCTYPE HTML>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
<script src="//ajax.googleapis./ajax/libs/jquery/1.8.0/jquery.min.js"></script>
<script type="text/javascript">
function myFunction(value)
{
    if(value!="All")
    {
        $.ajax(
        {
            type: "GET",
            url: '<?php echo $_SERVER['PHP_SELF']; ?>',
            data: { experience: value},
            success: function(data) {
                $('#resultDiv').html(data);
        }
    });
    }
    else
    {
        $('#resultDiv').html("Please select a value.");
    }
}
</script>
</head>

<body>
<p>
<label for="experience">Experience :</label>
<select id="experience" name="experience" onChange="myFunction(this.value)">
    <option value="All" selected="selected">All</option>
    <option value="Fresher">Fresher</option>
    <option value="Experienced">Experienced</option>
</select>
</p>
<div id="resultDiv">
Please select a value.
</div>
</body>
</html>

You cannot re-execute a PHP part on the same page. Rather use Ajax request to perform the action.

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