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I have a string: " \" ". I would like to escape all unescaped double-quotes, i.e. add a backslash before " if it's note there.

input = '" \\" "'
input.replace(???) == '\\" \\" \\"'

I've tried

input.replace(/(?!\\)"/g, '\\"')

It escapes second backslash twice ('\" \\" \"') for the reason I don't understand.

I've figured out

(' ' + input).replace(/([^\\])"/g, '$1\\"').slice(1)

But it looks ugly. It has to be a better way.

---

Update:

One more test case:

>> input = '" \\" \\\\" \\\\\\"'
-> '" \" \\" \\\"'
>> input.replace(???)
-> '\" \" \\\" \\\"'

None of my regular expressions can handle it.

I have a string: " \" ". I would like to escape all unescaped double-quotes, i.e. add a backslash before " if it's note there.

input = '" \\" "'
input.replace(???) == '\\" \\" \\"'

I've tried

input.replace(/(?!\\)"/g, '\\"')

It escapes second backslash twice ('\" \\" \"') for the reason I don't understand.

I've figured out

(' ' + input).replace(/([^\\])"/g, '$1\\"').slice(1)

But it looks ugly. It has to be a better way.

---

Update:

One more test case:

>> input = '" \\" \\\\" \\\\\\"'
-> '" \" \\" \\\"'
>> input.replace(???)
-> '\" \" \\\" \\\"'

None of my regular expressions can handle it.

• javascript
• regex
• escaping

Share Improve this question Follow edited Sep 12, 2011 at 2:43 NVI asked Sep 11, 2011 at 23:51 NVINVI 15.1k1717 gold badges6868 silver badges104104 bronze badges 3

• JS doesn't support lookbehinds, but I'm trying to emulate them. [^\] doesn't pile (throws SyntaxError). – NVI Commented Sep 12, 2011 at 0:15
• Ah sorry, I guess, it's me who got confused then ;) Right, \ is also the escape characters inside an expression. My apologies... deleted my ment as it does not make sense at all... – Felix Kling Commented Sep 12, 2011 at 0:16
• Anyways, the backslash is escaped because although \" does not match, " does. As your expression is not anchored, every position/character is tried to match. – Felix Kling Commented Sep 12, 2011 at 0:22

Add a ment  | 

3 Answers 3

Sorted by: Reset to default 4

What I have is scarcely better, but it does handle escaped backslashes too:

>>> var v= 'a\\"b'
>>> v
"a\"b"
>>> v.replace(/(\\*)(")/g, function(x) { var l = x.length; return (l % 2) ? x : x.substring(0,l-1) + '\\"' } )
"a\\"b"
>>> var v= 'a\\\\"b'
>>> v
"a\\"b"
>>> v.replace(/(\\*)(")/g, function(x) { var l = x.length; return (l % 2) ? x : x.substring(0,l-1) + '\\"' } )
"a\\"b"

If there are an odd number of slashes before a quote (1, 3, 5), the quote is already escaped; an even number (including zero), in needs escaping.

Made all the harder to read by the necessary of escaping the slashes in input and by the inability of the colorizer to understand the regexp expression...

Of course, you probably shouldn't even be doing this. If you have a raw string and you need something you can pass to (e.g.) eval, consider $.toJSON.

This worked for me:

var arf = input.replace(/(^|[^\\])"/g, '$1\\"');

It says, replace a quote, when preceded by beginning-of-string or anything-other-than-backslash, with backslash followed by quote.

String(str).replace(/[\\"']/g, "\\$&")
   .replace(/[\r\n\u2028\u2029]/g,
   function (x) {
     switch (x) {
     case '\n': return "\\n";
     case '\r': return "\\r";
     case '\u2028': return "\\u2028";
     case '\u2029': return "\\u2029";
     }
   })

The String call ensures that the input is a valid string.

The first replace will handle quotes and backslashes. The second handles embedded line terminators.

If you want to deal with an already quoted string, you can change the first replace to this:

'"' + String(str).replace(/^"|"$/g, "").replace(/[\\"]/g, "\\$&") + '"'

to unquote and requote.

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