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I am using the MIT App Inventor to create multiple light switches. Whenever I send a text from the Switch, the serial monitor prints each letter of the word on different lines. How can I change it to a whole text e.g. "1on" before showing a new line of text?

const int led1 = 2;
const int led2 = 3;
const int led3 = 4;

char v = 0;

void setup() {
  Serial.begin(9600);
  pinMode(led1, OUTPUT);
  pinMode(led2, OUTPUT);
  pinMode(led3, OUTPUT);
}

void loop() {
  if (Serial.available() > 0) {
    v = Serial.read();
    Serial.println(v);
    // Serial.print('\n');

    if (v == 'a') {
      digitalWrite(led1, HIGH);
    } else if (v == 'b') {
      digitalWrite(led1, LOW);
    }
    if (v == 'c') {
      digitalWrite(led2, HIGH);
    } else if (v == 'd') {
      digitalWrite(led2, LOW);
    }
    if (v == 'e') {
      digitalWrite(led3, HIGH);
    } else if (v == 'f') {
      digitalWrite(led3, LOW);
    }
  }
}

I am using the MIT App Inventor to create multiple light switches. Whenever I send a text from the Switch, the serial monitor prints each letter of the word on different lines. How can I change it to a whole text e.g. "1on" before showing a new line of text?

const int led1 = 2;
const int led2 = 3;
const int led3 = 4;

char v = 0;

void setup() {
  Serial.begin(9600);
  pinMode(led1, OUTPUT);
  pinMode(led2, OUTPUT);
  pinMode(led3, OUTPUT);
}

void loop() {
  if (Serial.available() > 0) {
    v = Serial.read();
    Serial.println(v);
    // Serial.print('\n');

    if (v == 'a') {
      digitalWrite(led1, HIGH);
    } else if (v == 'b') {
      digitalWrite(led1, LOW);
    }
    if (v == 'c') {
      digitalWrite(led2, HIGH);
    } else if (v == 'd') {
      digitalWrite(led2, LOW);
    }
    if (v == 'e') {
      digitalWrite(led3, HIGH);
    } else if (v == 'f') {
      digitalWrite(led3, LOW);
    }
  }
}

• arduino
• bluetooth

Share Improve this question Follow edited Jan 18 at 17:15 Dirk asked Jan 18 at 16:25 DirkDirk 2133 bronze badges 4

• What's your question? – robertklep Commented Jan 18 at 16:30
• That is correct& Your sketch works exactly as you described. If you do not need each letter on new line replace println() with print() – Mike Petrichenko Commented Jan 18 at 16:34
• Sorry, edited the message in. Instead of one character per line, I need the whole word before breaking to a new line. – Dirk Commented Jan 18 at 16:40
• @Dirk Below is the correct answer. – Mike Petrichenko Commented Jan 18 at 19:08

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1 Answer 1

Sorted by: Reset to default 0

use String or char array in line 5 and use readString() function to read all in line 16. Link

const int led1 = 2;
const int led2 = 3;
const int led3 = 4;

String v = 0; /* use String or char array */

void setup() {
  Serial.begin(9600);
  pinMode(led1, OUTPUT);
  pinMode(led2, OUTPUT);
  pinMode(led3, OUTPUT);
}

  void loop() {
  if (Serial.available() > 0) {
    v = Serial.readString(); /* use readString() function to read all */
    Serial.println(v);
    // Serial.print('\n');

    if (v == "1on") {
      digitalWrite(led1, HIGH);
    } else if (v == "1off") {
      digitalWrite(led1, LOW);
    }
    else if (v == "2on") {
      digitalWrite(led2, HIGH);
    } else if (v == "2off") {
      digitalWrite(led2, LOW);
    }
    else if (v == "3on") {
      digitalWrite(led3, HIGH);
    } else if (v == "3on") {
      digitalWrite(led3, LOW);
    }
  }
}

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