javascript - How can i delay a function - Stack Overflow

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Can someone assist me on how I can delay this function?

$('#customer_quote').lightbox_me({  
        centered: true, 
        closeSelect: ".close",
        onClose: function(){
            $('div.error').remove()
            }
        })  

 });

I want this lightbox to open after 7 seconds.

Can someone assist me on how I can delay this function?

$('#customer_quote').lightbox_me({  
        centered: true, 
        closeSelect: ".close",
        onClose: function(){
            $('div.error').remove()
            }
        })  

 });

I want this lightbox to open after 7 seconds.

• javascript
• jquery
• html
• css

Share Improve this question Follow asked Aug 10, 2012 at 15:26 breezybreezy 1,91811 gold badge1818 silver badges3535 bronze badges 2

• use setTimeout() electrictoolbox./using-settimeout-javascript – Carlo Moretti Commented Aug 10, 2012 at 15:29
• 1 Additional Resource: developer.mozilla/en-US/docs/DOM/window.setTimeout – Nope Commented Aug 10, 2012 at 15:32

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5 Answers 5

Sorted by: Reset to default 8

Use setTimeout():

setTimeout(lightbox, 7000);

function lightbox() {
    $('#customer_quote').lightbox_me({  
            centered: true, 
            closeSelect: ".close",
            onClose: function(){
                $('div.error').remove()
                }
            })  

     });
}

Give setTimeout a shot:

setTimeout(function() {
    $('#customer_quote').lightbox_me({
        centered: true,
        closeSelect: ".close",
        onClose: function() {
            $('div.error').remove()
        }
    });
}, 7000);​

setTimeout(function(){
$('#customer_quote').lightbox_me({  
        centered: true, 
        closeSelect: ".close",
        onClose: function(){
            $('div.error').remove()
            }
        })  

 });

}, 7000);

Check this link out: To delay JavaScript function call using jQuery

Seems like you just use setTimeout with 7000

Use setTimeout.

var delayedFunction = function() {
   /* your code */
}

setTimeout(delayedFunction, 7000);

The second argument stands for the number of miliseconds.

Note also that this evokes an asynchronous event. The execution of your code will not stop at the line with setTimeout for 7 seconds.

If you want to execute another code after this delay, you must do so in delayedFunction, when the event fires.

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