admin管理员组

文章数量:1317909

so I'm getting an email's HTML response back from the server and in jQuery I'm trying to render that response into a popup window.

I tried this at first:

postToServerWithAjax('/invite_preview', null, function (response) {
    window.open($(response), "popupWindow", "width=600,height=600,scrollbars=yes");
});



However that just opened up the Popup window with [object, object] in the URL. I tried .html() below

postToServerWithAjax('/invite_preview', null, function (response) {
    window.open($(response).html(), "popupWindow", "width=600,height=600,scrollbars=yes");
});

^ And this just returned a blank popup window


I then tried just a blank page, but my code keeps placing the HTML into the url bar:

window.open(response).html();



What am I missing to actually render the HTML into the new popup/page?


Found some examples here, and used the answers, but haven't gotten the HTML to render yet :(

display html code of response returned by ajax, Jquery

jQuery function to open link in new window

so I'm getting an email's HTML response back from the server and in jQuery I'm trying to render that response into a popup window.

I tried this at first:

postToServerWithAjax('/invite_preview', null, function (response) {
    window.open($(response), "popupWindow", "width=600,height=600,scrollbars=yes");
});



However that just opened up the Popup window with [object, object] in the URL. I tried .html() below

postToServerWithAjax('/invite_preview', null, function (response) {
    window.open($(response).html(), "popupWindow", "width=600,height=600,scrollbars=yes");
});

^ And this just returned a blank popup window


I then tried just a blank page, but my code keeps placing the HTML into the url bar:

window.open(response).html();



What am I missing to actually render the HTML into the new popup/page?


Found some examples here, and used the answers, but haven't gotten the HTML to render yet :(

display html code of response returned by ajax, Jquery

jQuery function to open link in new window

Share Improve this question edited May 23, 2017 at 12:24 CommunityBot 11 silver badge asked Dec 3, 2013 at 19:44 Leon GabanLeon Gaban 39k122 gold badges349 silver badges550 bronze badges
Add a ment  | 

1 Answer 1

Reset to default 8

The first parameter is a URL, not actual content, you have to write that to the window

postToServerWithAjax('/invite_preview', null, function (response) {
   var wind = window.open("", "popupWindow", "width=600,height=600,scrollbars=yes");
   wind.document.write(response);
});

本文标签: javascriptHow to render server response as HTML into a popup window jQueryStack Overflow