javascript - How do I call a function at start in Expressjsnodejs (Setup method) - Stack Overflow

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I want my worker server to pickup tasks from parent server immediately after it starts and keep pinging for pending tasks.

Given that Nodejs is a event driven, how do I make my express server make a rest call to server and start working immediately after start?

In a way, I am asking for setup method in Nodejs.

I want my worker server to pickup tasks from parent server immediately after it starts and keep pinging for pending tasks.

Given that Nodejs is a event driven, how do I make my express server make a rest call to server and start working immediately after start?

In a way, I am asking for setup method in Nodejs.

• javascript
• node.js
• express

Share Improve this question Follow edited Jul 18, 2014 at 7:17 raju asked Jul 3, 2014 at 12:35 rajuraju 5,0081717 gold badges6666 silver badges121121 bronze badges

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2 Answers 2

Sorted by: Reset to default 6

You have your server.js file (the one you call node server.js on).

Simply place whatever code you need to run at bootstrap there.

var express = require("express");
...

yourSetupFunction();

app.listen(1337);

I'm not sure what type of tasks you fetch from parent node. So I'm assuming you just want to know when the new server is ready to use and perform actions based on that.

The express documentation mentions about app.listen as a function that can be configured.

Here's the code block

app.listen = function(){
    var server = http.createServer(this);
    //yourBootstrap();
    return server.listen.apply(server, arguments);
};

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