javascript - JQuery UI slider error (TypeError: max.toFixed is not a function) - Stack Overflow

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There is a Jquery UI double range slider on my website. But I'm getting the slider's max and min values from my database.

  $.ajax({
          url: "init.php",
          type: "GET",
          data : {"method": "price"},
          async: false,
          success: function(data){
          var result = JSON.parse(data);
          price.min = result.min;
          price.max = result.max;
          }
        });

So i have a

price = {
max: 0,
min: 1000
};

object and i give the new values values to the parameters in the ajax success function above.

---

 $( "#slider-range" ).slider({
            range: true,
            min: price.min, //these don't work
            max: price.max,
            values: [ price.min, price.max ],
            slide: function( event, ui ) {
              $( "#amount" ).val( ui.values[ 0 ] + " Ft" + " - " + ui.values[ 1 ] + " Ft" );

            },
            change: function( event, ui){
              var values ={
                min: ui.values[0],
                max: ui.values[1]
              };
              filter("price",values);
            }
          });
          $( "#amount" ).val($( "#slider-range" ).slider( "values", 0 )
            + " Ft" + " - " + $( "#slider-range" ).slider( "values", 1 )+ " Ft");

Here is my JQuery UI double range slider object And I've got this error message in the console of the browser:

TypeError: max.toFixed is not a function[Learn More] jquery-ui.js:15006:26

There is a Jquery UI double range slider on my website. But I'm getting the slider's max and min values from my database.

  $.ajax({
          url: "init.php",
          type: "GET",
          data : {"method": "price"},
          async: false,
          success: function(data){
          var result = JSON.parse(data);
          price.min = result.min;
          price.max = result.max;
          }
        });

So i have a

price = {
max: 0,
min: 1000
};

object and i give the new values values to the parameters in the ajax success function above.

---

 $( "#slider-range" ).slider({
            range: true,
            min: price.min, //these don't work
            max: price.max,
            values: [ price.min, price.max ],
            slide: function( event, ui ) {
              $( "#amount" ).val( ui.values[ 0 ] + " Ft" + " - " + ui.values[ 1 ] + " Ft" );

            },
            change: function( event, ui){
              var values ={
                min: ui.values[0],
                max: ui.values[1]
              };
              filter("price",values);
            }
          });
          $( "#amount" ).val($( "#slider-range" ).slider( "values", 0 )
            + " Ft" + " - " + $( "#slider-range" ).slider( "values", 1 )+ " Ft");

Here is my JQuery UI double range slider object And I've got this error message in the console of the browser:

TypeError: max.toFixed is not a function[Learn More] jquery-ui.js:15006:26

• javascript
• jquery
• ajax
• jquery-ui

Share Improve this question Follow asked Jul 27, 2017 at 18:30 Howard FringHoward Fring 30511 silver badge1313 bronze badges 20

• And how do you return those values from the ajax call ? – adeneo Commented Jul 27, 2017 at 18:32
• price.min = result.min; price.max = result.max; – Howard Fring Commented Jul 27, 2017 at 18:32
• this is in the success function – Howard Fring Commented Jul 27, 2017 at 18:33
• 1 async : false is deprecated in modern browsers, and shouldn't be used. – adeneo Commented Jul 27, 2017 at 18:36
• 1 I converted it to number and now it works, thanks @adeneo – Howard Fring Commented Jul 27, 2017 at 19:07

 |  Show 15 more ments

1 Answer 1

Sorted by: Reset to default 12

The solution:

min: Number(price.min),
max: Number(price.max),

thanks @adeneo

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