javascript - How to detect a MouseUp event outside the window? - Stack Overflow

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I am looking for jQuery solution to detect mouseup outside the window. That is, after the mouse has been downed inside the window, dragged outside while still down, and then released outside, is when the event should fire.

I tried document.mouseup = function() {}, it didn't help. I tried to follow the example here, but couldn't properly understand it (I even left a ment asking for help, but no help yet..:( )

I am looking for jQuery solution to detect mouseup outside the window. That is, after the mouse has been downed inside the window, dragged outside while still down, and then released outside, is when the event should fire.

I tried document.mouseup = function() {}, it didn't help. I tried to follow the example here, but couldn't properly understand it (I even left a ment asking for help, but no help yet..:( )

• javascript
• jquery

Share Improve this question Follow edited May 23, 2017 at 12:33 CommunityBot 111 silver badge asked Feb 16, 2013 at 16:34 NedStarkOfWinterfellNedStarkOfWinterfell 5,2432828 gold badges112112 silver badges204204 bronze badges 2

• 4 I believe it should be document.onmouseup – Fabrício Matté Commented Feb 16, 2013 at 16:38
• Yeah yeah, I mean that actually...:D – NedStarkOfWinterfell Commented Feb 16, 2013 at 17:09

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1 Answer 1

Sorted by: Reset to default 7

I have a website that uses this event and it works as you described:

$(window).on('mouseup', function(){
   //your code here
});

Note: only tested in jQuery 1.8.3, but it should work in 1.9

jsFiddle confirms. Works in jQuery 1.9.1 and 2 beta: http://jsfiddle/udRNx/1/

In case you didn't know, this piece of code must be placed in either $(document).ready(fn) or $(window).onload(fn).

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