admin管理员组文章数量:1310012
I have a function like this that does an ajax call to grab some data from a database.
function db (content) {
$.post('/ajax/db.php', {
operation:operation,
content:content
}, function(data)
{
console.log(data);
return data;
});
}
console.log(data);
gives me the data that I want.
However how do I pass data
to function db so that I can do something like:
var returnedData = db ('content');
Thanks!
I have a function like this that does an ajax call to grab some data from a database.
function db (content) {
$.post('/ajax/db.php', {
operation:operation,
content:content
}, function(data)
{
console.log(data);
return data;
});
}
console.log(data);
gives me the data that I want.
However how do I pass data
to function db so that I can do something like:
var returnedData = db ('content');
Thanks!
Share Improve this question asked Sep 25, 2010 at 18:03 MarkMark 33.7k34 gold badges108 silver badges139 bronze badges1 Answer
Reset to default 9AJAX Operations are asynchronous so returning it directly isn't an option, not unless you make it synchronous (which locks up the browser). Instead, you should pass the data onto the next function in the callback, like this:
function db (content) {
$.post('/ajax/db.php', {
operation:operation,
content:content
}, function(data)
{
nextFunction(data);
});
}
Or make it take a callback so you can pass the function that will get the data, when it's ready, like this:
function db (content, callback) {
$.post('/ajax/db.php', {
operation:operation,
content:content
}, callback);
}
Then call it providing the callback function, for example:
db('content', function(data) {
//do something with data
});
本文标签: jqueryjavascript function return dataStack Overflow
版权声明:本文标题:jquery - javascript function return data - Stack Overflow 内容由网友自发贡献,该文观点仅代表作者本人, 转载请联系作者并注明出处:http://www.betaflare.com/web/1741856757a2401387.html, 本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容,一经查实,本站将立刻删除。
发表评论