admin管理员组文章数量:1309955
I've an Azure function app written in C# which runs in dotnet 8 isolated mode. The function app is hosted under a Linux app service plan and needs to invoke smbclient command. This is what my code looks like:
public class FileShareDownload
{
private readonly ILogger<FileShareDownload> _logger;
public FileShareDownload(ILogger<FileShareDownload> logger)
{
_logger = logger;
}
[Function("FileShareDownload")]
public async Task<IActionResult> Run([HttpTrigger(AuthorizationLevel.Anonymous, "get", "post")] HttpRequest req)
{
_logger.LogInformation("Processing GetFileList request.");
string requestBody = await new StreamReader(req.Body).ReadToEndAsync();
var fileShareRequest = System.Text.Json.JsonSerializer.Deserialize<FileShareDownloadRequest>(requestBody);
if (fileShareRequest == null
|| string.IsNullOrEmpty(fileShareRequest.FileShareBasePath)
|| string.IsNullOrEmpty(fileShareRequest.FileShareDirectoryPath)
|| string.IsNullOrEmpty(fileShareRequest.Username)
|| string.IsNullOrEmpty(fileShareRequest.Password))
{
return new BadRequestObjectResult("Invalid request.");
}
// Use smbclient to list files in the file share path
string smbClientCommand = $"smbclient {fileShareRequest.FileShareBasePath} -U {fileShareRequest.Username}%{fileShareRequest.Password} -c \"cd {fileShareRequest.FileShareDirectoryPath.Replace("/", "; cd ")} ; ls\" -d 2";
_logger.LogWarning("Executing Command: " + smbClientCommand);
_logger.LogWarning("Result of date Process " + RunCommandWithBash("date"));
_logger.LogWarning("Result of help Process " + RunCommandWithBash("help"));
var processInfo = new ProcessStartInfo("bash", $"-c \"{smbClientCommand}\"")
{
RedirectStandardOutput = true,
RedirectStandardError = true,
UseShellExecute = false,
CreateNoWindow = true
};
var process = new Process
{
StartInfo = processInfo
};
process.Start();
//string result = await process.StandardOutput.ReadToEndAsync();
//string error = await process.StandardError.ReadToEndAsync();
string result = process.StandardOutput.ReadToEnd();
string error = process.StandardError.ReadToEnd();
process.WaitForExit();
_logger.LogWarning($"smbclient standard output: {result}");
_logger.LogWarning($"smbclient standard error: {error}");
if (process.ExitCode != 0)
{
_logger.LogError($"smbclient error: {error}");
return new StatusCodeResult(StatusCodes.Status500InternalServerError);
}
result = RunCommandWithBash(smbClientCommand);
_logger.LogWarning("New result: " + result);
_logger.LogWarning($"Received response: {result}");
return new OkObjectResult(result);
}
public string RunCommandWithBash(string command)
{
var psi = new ProcessStartInfo();
psi.FileName = "/bin/bash";
psi.Arguments = command;
psi.RedirectStandardOutput = true;
psi.UseShellExecute = false;
psi.CreateNoWindow = true;
using var process = Process.Start(psi);
process.WaitForExit(30000);
var output = process.StandardOutput.ReadToEnd();
return output;
}
}
When I test the function app, the response from running the bash commands is always blank. Here is what it looks like:
When I copy paste the command and execute it inside kudu ssh console, it works fine and gives me this response:
2:
Can someone please explain why is my function app either not executing the bash commands properly or not showing me the output correctly?
A bit of extra background, we needed a function app that would connect to file shares on Azure VMs and read files. We first tried making the function app which used mpr.dll to connect to file shares under Windows App Service Plan but discovered that the Azure Sandbox for Windows App service plan blocks connectivity on port 445 which is used for SMB. We were advised by Microsoft to switch to Linux App Service Plan because it does not have this limitation however we can't use mpr.dll on linux and have to use smbclient instead.
本文标签: Executing a Linux bash command from Azure C function appStack Overflow
版权声明:本文标题:Executing a Linux bash command from Azure C# function app - Stack Overflow 内容由网友自发贡献,该文观点仅代表作者本人, 转载请联系作者并注明出处:http://www.betaflare.com/web/1741795221a2397897.html, 本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容,一经查实,本站将立刻删除。
发表评论