regex - Replace string between "[]" with javascript using regexp - Stack Overflow

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I have a string ing back from a webservice the contains open brackets like such "[]" so the string would look like something like this:

[1] blabh balh blah

I would like to write a regexp that would remove the "[1]" or anything between open brackets. Right now I've tried something like:

var regexp = /\[[]\\]/g;

but this does not work. I'm stumbling on my own two feet here. I simply just want to find anything that starts with "[" and ends with "]" and replace everything in the middle including the open and closed brackets. Any help or guidance would be much appreciated.

I have a string ing back from a webservice the contains open brackets like such "[]" so the string would look like something like this:

[1] blabh balh blah

I would like to write a regexp that would remove the "[1]" or anything between open brackets. Right now I've tried something like:

var regexp = /\[[]\\]/g;

but this does not work. I'm stumbling on my own two feet here. I simply just want to find anything that starts with "[" and ends with "]" and replace everything in the middle including the open and closed brackets. Any help or guidance would be much appreciated.

• javascript
• regex

Share Follow edited Feb 21, 2013 at 3:19 Jess 25.1k2121 gold badges130130 silver badges155155 bronze badges asked Feb 21, 2013 at 2:53 MiguelMiguel 2,07955 gold badges2929 silver badges5353 bronze badges 1

• maybe /\[[0-9]*\]/; No need for the g flag because you don't want to replace globally. – Jess Commented Feb 21, 2013 at 2:55

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2 Answers 2

Sorted by: Reset to default 9

This should work:

var str = '[1] blabh balh blah';
str = str.replace(/\[.*?\]\s?/g, '');

If you have nested brackets regexp might no be the best option though.

Is using regexp a requirement? If not, a simple solution might be:

var myString = '[1] Bob Loblaw is the man';
myString = myString.slice(myString.indexOf(']')+1);

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