javascript - PHP regular expressions (phonenumber) - Stack Overflow

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I'm having some trouble with a regular expression for phone numbers. I am trying to create a regex that is as broad as possible for european phone numbers. The phone number can start with a + or with two leading 0's, followed by a number in between 0 and 40. this is not necessary however, so this first part can also ignored. After that, it should all be numbers, grouped into pairs of at least two, with a whitespace or a - inbetween the groups.

The regex I have put together can be found below.

/((\+|00)+[0-4]+[0-9]+)?([ -]?[0-9]{2,15}){1,5}/

This should match the following structures

0031 34-56-78
0032123456789
0033 123 456 789
0034-123-456-789

+35 34-56-78
+36123456789
+37 123 456 789
+38-123-456-789
...

What it also matches according to my javascript

+32 a54b 67-0:

So I must have made a mistake somewhere, but I really can't see it. Any help would be appreciated.

I'm having some trouble with a regular expression for phone numbers. I am trying to create a regex that is as broad as possible for european phone numbers. The phone number can start with a + or with two leading 0's, followed by a number in between 0 and 40. this is not necessary however, so this first part can also ignored. After that, it should all be numbers, grouped into pairs of at least two, with a whitespace or a - inbetween the groups.

The regex I have put together can be found below.

/((\+|00)+[0-4]+[0-9]+)?([ -]?[0-9]{2,15}){1,5}/

This should match the following structures

0031 34-56-78
0032123456789
0033 123 456 789
0034-123-456-789

+35 34-56-78
+36123456789
+37 123 456 789
+38-123-456-789
...

What it also matches according to my javascript

+32 a54b 67-0:

So I must have made a mistake somewhere, but I really can't see it. Any help would be appreciated.

• php
• javascript
• regex

Share Improve this question Follow edited Oct 24, 2011 at 12:23 Michiel Standaert asked Oct 24, 2011 at 12:02 Michiel StandaertMichiel Standaert 4,17677 gold badges2929 silver badges5050 bronze badges 9

• 1 Just a small note: You use + in places where you mean "one occurrence". + however means "at least one". So you might want to consider erasing all + in the first part of the regex, as every single group in there should occur exactly once and the following ? will then make the whole thing optional. – Till Helge Commented Oct 24, 2011 at 12:07
• Use \s instead of putting whitespace directly – Shameer Commented Oct 24, 2011 at 12:08
• It's the [0-9]{2,15} that matches, the first regex part being optional. As the answers say, you wanted to constraint the match to the whole string (start end assertions). – mario Commented Oct 24, 2011 at 12:08
• 1 EU numbers start with 3 or 4 (except for Faroe Islands(298) and Greenland(299)) and some countries got 3 numbers in there prefix for country code so i expanded on the regex a bit and made it so it only had 2 capture groups (prefix and number) ^((?:00|\+)(?:[34][0-9]{1,2}|298|299))?[ -]?((?:[0-9]{2,15}[ -]?){1,5})$ – Blem Commented Oct 24, 2011 at 12:38
• 1 here is an example: if (ereg ("^((?:00|\+)(?:[34][0-9]{1,2}|298|299))?[ -]?((?:[0-9]{2,15}[ -]?){1,5})$", $var, $regs)) { $countrycode = $regs[1]; $number = $regs[2]; } (sorry it dos not look good in ments) – Blem Commented Oct 24, 2011 at 13:05

 |  Show 4 more ments

3 Answers 3

Sorted by: Reset to default 10

The problem is that you don't use anchors ^ $ to define the start and ending of the string and will therefore find a match anywhere in the string.

/^((\+|00)+[0-4]+[0-9]+)?([ -]?[0-9]{2,15}){1,5}$/

Adding anchors will do the trick. More about these meta characters can be found here.

Try this, may be can help you.

if (ereg("^((\([0-9]{3}\) ?)|([0-9]{3}-))?[0-9]{3}-[0-9]{4}$",$var)) 
{
    $valid = true; 
}

Put ^ in the beginning of the RegExp and $ in the end.

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