javascript - Is there a better way to ensure a number is positive? - Stack Overflow

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I want to ensure that a number is positive, and if not return its mirror

I have started with this

var pos = Math.sqrt(x*x);

Is there a better, more efficient way?

I want to ensure that a number is positive, and if not return its mirror

I have started with this

var pos = Math.sqrt(x*x);

Is there a better, more efficient way?

• javascript
• math

Share Follow asked Feb 13, 2012 at 10:21 Mild FuzzMild Fuzz 30.8k3434 gold badges105105 silver badges151151 bronze badges 1

• 3 I think Math.sqrt(x*x) is the most inefficient way :) – Sergey Gavruk Commented Feb 13, 2012 at 10:27

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3 Answers 3

Sorted by: Reset to default 8

Use Math.abs.

Example: document.write(Math.abs(-5)).

You should use Math.abs(number) to do that.

The abs() method returns the absolute value of a number.
var pos = Math.abs(x)

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