arrays - How to split() string with brackets in Javascript - Stack Overflow

admin管理员组

文章数量:1290926

i just want to make

str = "a(bcde(dw)d)e"

to

arr = {"a", "(bcde)", "(dw)", "(d)", "e"}

What regEx can i use in str.split()?

PS: Explanations || helpful links wele.

Examples:

s: "a(bcdefghijkl(mno)p)q" --> [ 'a', '(bcdefghijkl)', '(mno)', '(p)', 'q' ]
s: "abc(cba)ab(bac)c" --> [ 'abc', '(cba)', 'ab', '(bac)', 'c' ]

i just want to make

str = "a(bcde(dw)d)e"

to

arr = {"a", "(bcde)", "(dw)", "(d)", "e"}

What regEx can i use in str.split()?

PS: Explanations || helpful links wele.

Examples:

s: "a(bcdefghijkl(mno)p)q" --> [ 'a', '(bcdefghijkl)', '(mno)', '(p)', 'q' ]
s: "abc(cba)ab(bac)c" --> [ 'abc', '(cba)', 'ab', '(bac)', 'c' ]

• javascript
• arrays
• regex
• string
• split

Share Improve this question Follow edited Apr 21, 2017 at 8:48 Jannis asked Apr 21, 2017 at 7:57 JannisJannis 10711 gold badge22 silver badges88 bronze badges 5

• 2 your result looks a bit strange || invalid. – Nina Scholz Commented Apr 21, 2017 at 7:59
• 4 Is the result supposed to be an array of strings, ["a", "(bcde)", "(dw)", "(d)", "e"]? – nnnnnn Commented Apr 21, 2017 at 8:01
• Yes, it is supposed to be an array of strings. – Jannis Commented Apr 21, 2017 at 8:04
• Can you add a few edge cases? What about "a(b)c(d)e"? What about "(a(b)c(d)e)"? – yunzen Commented Apr 21, 2017 at 8:39
• What about "(a(b(c)))d(e)"? – yunzen Commented Apr 21, 2017 at 8:47

Add a ment  | 

4 Answers 4

Sorted by: Reset to default 4

Go through each parentheses using a counter:

array = [], c = 0;

'abc(cba)ab(bac)c'.split(/([()])/).filter(Boolean).forEach(e =>
// Increase / decrease counter and push desired values to an array
e == '(' ? c++ : e == ')' ? c-- : c > 0 ? array.push('(' + e + ')') : array.push(e)
);

console.log(array)

Edit

str = "a(bcde(dw)d)e"
    // replace any `(alpha(` by `(alpha)(`
    str1 = str.replace(/\(([^)]+)\(/g, '($1)(');
    // replace any `)alpha)` by )(alpha)`
    str2 = str1.replace(/\)([^(]+)\)/g, ')($1)');
    // prefix any opening parenthesis with #--# (just a character string unlikly to appear in the original string)
    str3 = str2.replace(/\(/g, '#--#(');
    // prefix any closing parenthesis with  #--#
    str4 = str3.replace(/\)/g, ')#--#');
    // remove any double `#--#`
    str5 = str4.replace(/(#--#)+/g, '#--#');
    // split by invented character string
    arr = str5.split('#--#');
    console.log(arr);

Old wrong answer

    str = "a(bcde(dw)d)e"
    console.log(str.split(/[()]/));

This looks a little bit weird, but it's like this.

str is string which has a split method. This can take a string or a regular expression as argument. A string will be delimited by " and a RegExp by /. The brackets [] wrap a character class which means any one of the characters inside. Then inside we have the two parentheses () which are the two characters we are looking for.

I don't think the result you want is possible without modifying the values of the array after the split. But if you want to be able to split the string based on 2 symbols (in this case the brackets '(' and ')') you can do this:

var arr = str.split("(").toString().split(")");

It returns an array with the "words" of the string.

I hope I could help.

Given that the desired output includes characters that aren't in the string, e.g., adding closing or opening parentheses to the substrings in the outer part of the nested parentheses, it will be necessary to make some changes to the individual substrings after they are extracted one way or another.

Maybe something like this:

function getGroups(str) {
  var groups = str.match(/(?:^|[()])[^()]+/g)
  if (!groups) return []
  var parenLevel = 0
  return groups.map(function(v) {
    if (v[0] === "(") {
      parenLevel++
    } else if (v[0] === ")") {
      parenLevel--
    }
    v = v.replace(/[()]/,"")
    return parenLevel > 0 ? "(" + v + ")" : v
  })
}

console.log(JSON.stringify( getGroups("a(bcde(dw)d)e") ))
console.log(JSON.stringify( getGroups("abc(cba)ab(bac)c") ))
console.log(JSON.stringify( getGroups("ab(cd)ef(gh)") ))
console.log(JSON.stringify( getGroups("ab(cd)(e(f(gh)i))") ))
console.log(JSON.stringify( getGroups("(ab(c(d))ef(gh)i)") ))

本文标签： arraysHow to split() string with brackets in JavascriptStack Overflow