javascript - Parse YYYY-MM-DD dates using the local timezone - Stack Overflow

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In javascript, if I specify the date as MM/DD/YYYY, I can use new Date() to parse it as the local timezone:

>>> new Date('01/01/1970')
Date {Thu Jan 01 1970 00:00:00 GMT-0500 (EST)}

However, if I specify the date as YYYY-MM-DD, it assumes that I'm giving the date in the UTC timezone:

>>> new Date('1970-01-01')
Date {Wed Dec 31 1969 19:00:00 GMT-0500 (EST)}

Is there an easy way to tell the date parser to use the local timezone when parsing 'YYYY-MM-DD' dates? Or do I need to use .replace(/^(\d{4})-(\d{2})-(\d{2})$/, '$2/$3/$1') to fix it first?

In javascript, if I specify the date as MM/DD/YYYY, I can use new Date() to parse it as the local timezone:

>>> new Date('01/01/1970')
Date {Thu Jan 01 1970 00:00:00 GMT-0500 (EST)}

However, if I specify the date as YYYY-MM-DD, it assumes that I'm giving the date in the UTC timezone:

>>> new Date('1970-01-01')
Date {Wed Dec 31 1969 19:00:00 GMT-0500 (EST)}

Is there an easy way to tell the date parser to use the local timezone when parsing 'YYYY-MM-DD' dates? Or do I need to use .replace(/^(\d{4})-(\d{2})-(\d{2})$/, '$2/$3/$1') to fix it first?

• javascript
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Share Improve this question Follow asked Jul 27, 2013 at 3:17 rampionrampion 89.1k4949 gold badges204204 silver badges320320 bronze badges 4

• According to developer.mozilla/en-US/docs/Web/JavaScript/Reference/…, "If you do not specify a time zone, the local time zone is assumed." I'm not sure why this is not the case. – mash Commented Jul 27, 2013 at 3:21
• 2 or new Date('1970-01-01'.replace(/-/g,'/')) and it will parsed as localtime. – fbynite Commented Jul 27, 2013 at 5:04
• 1 I think this thread can give you a lot of insights about Data.parse :) – Mike Li Commented Jul 27, 2013 at 5:41
• Great question. This issue drove me crazy for hours. – Josh Buchea Commented Jul 21, 2015 at 22:43

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2 Answers 2

Sorted by: Reset to default 5

The function bellow will do exactly what you want, so you can pass a string in the format "YYYY-MM-DD" and it will return a Date object in your local time zone.

function yyyymmddToLocalDate(isoString) {
  const [year, month, day] = isoString.split('-');
  return new Date(year, month - 1, day);
}

If you're in Brazil for example and call it yyyymmddToLocalDate('2020-10-07') it will return Wed Oct 07 2020 00:00:00 GMT-0300 (Brasilia Standard Time)

Date.parse behaves as follows:

http://www.ecma-international/ecma-262/5.1/#sec-15.9.4.2

The function first attempts to parse the format of the String according to the rules called out in Date Time String Format (15.9.1.15). If the String does not conform to that format the function may fall back to any implementation-specific heuristics or implementation-specific date formats.

http://www.ecma-international/ecma-262/5.1/#sec-15.9.1.15

ECMAScript defines a string interchange format for date-times based upon a simplification of the ISO 8601 Extended Format. The format is as follows: YYYY-MM-DDTHH:mm:ss.sssZ

Z is the time zone offset specified as “Z” (for UTC) or either “+” or “-” followed by a time expression HH:mm

The value of an absent time zone offset is “Z”.

So in the first case, since it doesn't fit the Date Time String Format, the implementation-specific parse takes effect (which happens to be based on local time). In the second case, it does fit the DTSF, so it is parsed as if the time zone was unspecified (which is supposed to be UTC), hence the disparity

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