regex - Javascript : Extracting the digits from different positions from a string? - Stack Overflow

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I have a string like below

Original string  : results

1apple23oranges  : 1 , 23

4apples1oranges  : 4, 1

25oranges        : 25

By regular expression or any, i can't figure out how to get the above results as pure digits in javascript.

Any idea pls?

I have a string like below

Original string  : results

1apple23oranges  : 1 , 23

4apples1oranges  : 4, 1

25oranges        : 25

By regular expression or any, i can't figure out how to get the above results as pure digits in javascript.

Any idea pls?

• javascript
• regex

Share Improve this question Follow edited May 10, 2011 at 6:58 kapa 78.7k2121 gold badges165165 silver badges178178 bronze badges asked May 10, 2011 at 6:55 Kathy001Kathy001 111 gold badge11 silver badge11 bronze badge

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4 Answers 4

Sorted by: Reset to default 7

Use the regular expression \d+, which means any digit from 0 to 9 (\d) repeated one or more times (+). The qualifier g will make the search global (ie: don't stop on the first hit).

resultArray = original.match(/\d+/g);

This will result an array with all the numbers, to join them using ", " a separator, use the function join()

resultString = original.match(/\d+/g).join(", ");

'1apple23oranges'.match(/\d+/g);

Use match function on your string object with expression .match(/\d+/g).

Eg. var a = "1apple23oranges"

 var res = a.match(/\d+/g)

You can separate each values by ma.

Try "1apple23oranges".match(/(\d+)/g);

Note: If you need the digits as integer value then you have to use parseInt for that. If you are using jQuery then you can have all the integers in an array

var arr = new Array(); 
$.each("1apple23oranges".match(/(\d+)/g), function(index, value){ arr.push(parseInt(value, 10));});

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