In case spawn of electron, I can't see output of process in realtime - Stack Overflow

admin管理员组

文章数量:1291023

I'm beginer of electron, and I learned I can execute external program with spawn function. But, when I execute external program, I can't see output data of the program immediately.

This is my external python program. You can see it's a simple program printing "Tick" and saving it to the file. And it works fine, when I execute it manually. I can see the "Tick" every each second.

import time

while True:
    with open("tick.txt", "a") as f:
        f.write("Tack")
        f.close()
    print("Tick")
    time.sleep(1)

But, when I execute it by electron spawn() with following code, I can not see "Tick" on the VS-Code terminal.

function ExecuteTick()
{
    try {
        console.log("Executing Tick");
        const child_process = spawn(
            "python",
            [
                "../converter/tick.py"
            ]);

        child_process.stdout.on('data', (data) => {
            console.log(data.toString());
        });
        child_process.stderr.on('data', (data) => {
            console.error("Tick-Error: " + data);
        });
        child_process.on('close', (code) => {
            console.log("Tick-End: " + code);
        });
    }catch(err){
        console.error("Error on executing Tick - " + err);
    }
}

I believe this Tick program run properly in the background. Because I can see "Tack" from the 'tick.txt' file.

So, my problem is that, When I execute Tick program by electron spawn(), I can not see stdout from the Tick program in realtime, even though it runs properly.

Could you give me some advice for this problem? Thanks.

本文标签： In case spawn of electronI can39t see output of process in realtimeStack Overflow