Javascript if else statement optimisation - Stack Overflow

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I want to ask about optimisation in JavaScript if else statement.I have the code like this

if ( thisIsTrue )
    printMe("someMessage");

And the code can be optimisation like this

thisIsTrue && printMe("someMessage");

The question is what the code of thisIsTrue && printMe("someMessage"); only works in statement who has been return true.

What if the return is false?

I want to ask about optimisation in JavaScript if else statement.I have the code like this

if ( thisIsTrue )
    printMe("someMessage");

And the code can be optimisation like this

thisIsTrue && printMe("someMessage");

The question is what the code of thisIsTrue && printMe("someMessage"); only works in statement who has been return true.

What if the return is false?

• javascript

Share Improve this question Follow edited Jun 7, 2012 at 23:27 Igor F. 2,69922 gold badges3333 silver badges4141 bronze badges asked Jan 5, 2012 at 8:07 viyancsviyancs 2,33944 gold badges4040 silver badges7272 bronze badges 1

• 2 What about !thisIsFalse && printMe("someMessage"). However, this is not really an optimization; all it does is make the code more difficult to read. I would go with your first example, and add braces too. – Peter Commented Jan 5, 2012 at 8:11

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5 Answers 5

Sorted by: Reset to default 13

You should avoid turning your code into a puzzle either for someone else, or for the future you. There is nothing to be gained from mixing your conditions with your output. It's not going to "optimize" anything, and it will cost you lots of time in the future as you try to debug this.

I would argue you should err on the side of MORE verbosity not less.

thisIsTrue ? printMe("is true") : printMe("is false");

Although this is not optimisation and not suggested but i would explain the details.

in a bination of operands like A && B , 1st the operand A will be executed and if it return true the second operand will be executed otherwise it will be terminated because if the 1st operand is true the result will depends on the second operand else if the 1st is false result will surely be false irrespective of the second operand so it doesnot execute the second one. so

true && alert("someMessage"); will show alert 

and

!false && alert("someMessage....."); will also show

binding the above two, you can write is as

condition ? alert("someMessage") : alert("someMessage.....");

fiddle : http://jsfiddle/9q2jC/1/

This is hardly an optimisation (in terms of performance).

Also, these two forms are not identical.

The latter is an expression, while the former is a statement.

If you have a series of If-Then-Else statements, you should try your best to organize them from most likely to least likely. This way the program doesn't have to traverse all the unlikely conditions to get to the likely ones, which will be called more often.

A monly used tactic to wring whatever overhead might be left out of a large group of simple conditional statements is replacing If-Then-Else's with Switch statements. This is a tough one to qualify. Performance varies widely, although you almost always e out with some kind of improvement, even if it is small. As always, proper code design is much more important. See there are good test cases with switch and if elseif else

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