php - Regular expression for clean javascript comments of type- Stack Overflow

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I´m using the following REGEXP:

$output = preg_replace( "/\/\/(.*)\\n/", "", $output );

The code works well BUT!!!!, when a URL like (), the code replaces it... (http://)

What can you do to no replace that URLs.

Thanks,

I´m using the following REGEXP:

$output = preg_replace( "/\/\/(.*)\\n/", "", $output );

The code works well BUT!!!!, when a URL like (http://this_is_not_a_ment./kickme), the code replaces it... (http://)

What can you do to no replace that URLs.

Thanks,

• php
• javascript
• html
• regex
• text

Share Improve this question Follow asked Nov 25, 2010 at 15:44 CRISHK CorporationCRISHK Corporation 3,00866 gold badges3939 silver badges5353 bronze badges 2

• 2 You need some kind of parser that can distinguish between code and ments. – Gumbo Commented Nov 25, 2010 at 15:46
• 2 You should look at this answer: stackoverflow./questions/1732348/… – Don Roby Commented Nov 25, 2010 at 15:53

Add a ment  | 

2 Answers 2

Sorted by: Reset to default 8

You need a regular expression that can distinguish between the code and the ments. In particular, since the sequence of // can either be in a string or a ment, you just need to distinguish between strings and ments.

Here’s an example that might do this:

/(?:([^\/"']+|\/\*(?:[^*]|\*+[^*\/])*\*+\/|"(?:[^"\\]|\\.)*"|'(?:[^'\\]|\\.)*')|\/\/.*)/

Using this in a replace function while replacing the matched string with the match of the first subpattern should then be able to remove the // style ments.

Some explanation:

• [^/"']+ matches any character that is not the begin of a ment (both //… and /*…*/) or of a string
• /\*(?:[^*]|\*+[^*/])*\*+/ matches the /* … */ style ments
• "(?:[^"\\]|\\.)*" matches a string in double quotes
• '(?:[^'\\]|\\.)*' matches a string in single quotes
• \/\/.* finally matches the //… style ments.

As the first three constructs are grouped in a capturing group, the matched string is available and nothing is changed when replacing the matched string with the match of the first subpattern. Only if a //… style ment is matched the match of the first subpattern is empty and thus it’s replaced by an empty string.

But note that this may fail. I’m not quite sure if it works for any input.

$output = preg_replace( "/(?<!\:)\/\/(.*)\\n/", "", $output );

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