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Trying to group up array of object to get unique properties with Lodash

But it takes undefined like unique property if property does not exists

Is there way how to avoid it? and left only existing properties ?

So i'm going to achieve only My Office 1 but with my solution getting undefined and My Office 1 Example array

[
        {office: null},
        {office: 
            {
                name: 'My Office 1'
            }
        }
]

code

Object.keys(_.groupBy(arr, 'office.name')).map((office, index) { ... }

Trying to group up array of object to get unique properties with Lodash

But it takes undefined like unique property if property does not exists

Is there way how to avoid it? and left only existing properties ?

So i'm going to achieve only My Office 1 but with my solution getting undefined and My Office 1 Example array

[
        {office: null},
        {office: 
            {
                name: 'My Office 1'
            }
        }
]

code

Object.keys(_.groupBy(arr, 'office.name')).map((office, index) { ... }

• javascript
• lodash

Share Improve this question Follow asked May 24, 2017 at 9:17 Андрей ГузюкАндрей Гузюк 2,16466 gold badges3131 silver badges5656 bronze badges 1

• 1 I don't think that's possible. undefined is a valid grouping in this case. You'll have to do a filter before or after your groupBy. – shotor Commented May 24, 2017 at 9:41

Add a ment  | 

1 Answer 1

Sorted by: Reset to default 12

You can just filter out the objects, which do not have the path.

let objects = [
  {office: null},
  {office: {name: 'My Office 1'}},
  {office: {name: 'My Office 2'}},
  {office: {name: 'My Office 1'}},
];

let path = 'office.name';
let grouped = _(objects)
  .filter(object => _.has(object, path))
  .groupBy(path)
  .value();

console.log(grouped);

<script src="https://cdnjs.cloudflare./ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>

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