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Is there a way in javascript to plot x,y coordinates so they fall into a circle rather than a square?
For example if I have the following code:
circleRadius = 100;
context.drawImage(img_elem, dx, dy, dw, dh);
I need to figure out a combination of x,y values that would fall inside a 100 pixel circle.
Thanks!
Is there a way in javascript to plot x,y coordinates so they fall into a circle rather than a square?
For example if I have the following code:
circleRadius = 100;
context.drawImage(img_elem, dx, dy, dw, dh);
I need to figure out a combination of x,y values that would fall inside a 100 pixel circle.
Thanks!
Share Improve this question edited Jul 15, 2014 at 16:47 Dan Is Fiddling By Firelight 6,06118 gold badges79 silver badges131 bronze badges asked Jan 16, 2011 at 20:20 RigilRigil 5495 gold badges9 silver badges13 bronze badges 1- 3 The set of (x, y) points within a circle of radius r is given by the inequality x^2 + y^2 < r^2 – Tom Crockett Commented Jan 16, 2011 at 20:27
5 Answers
Reset to default 7- choose an x at random between -100 and 100
- a circle is defined by
x^2 + y^2 = r^2
, which in your case equals 100^2 = 10000 - From this equation you can get that
y^2 = 10000 - x^2
, therefore the points with a chosen x andy = +/-sqrt(10000 - x^2)
will lye on the circle. - choose an y at random between the two coordinates found at point 3
- You're set!
EDIT: In JS:
var radius = 100;
x = Math.random() * 2 * radius - radius;
ylim = Math.sqrt(radius * radius - x * x);
y = Math.random() * 2 * ylim - ylim;
Another edit: a jsFiddle Example
If you want equidistributed coordinates you better go for
var radius = 100
var center_x = 0
var center_y = 0
// ensure that p(r) ~ r instead of p(r) ~ constant
var r = radius*Math.sqrt(Math.random(1))
var angle = Math.sqrt(2*Math.PI)
// compute desired coordinates
var x = center_x + r*Math.cos(angle);
var y = center_y + r*Math.sin(angle);
If you want more points close to the middle then use
var r = radius*Math.random(1)
instead.
not sure what you mean for javascript but
x = R*cos(theta)
and y = R*sin(theta)
are the Cartesian points for a circle. R is the radius of course and theta is the angle which goes from 0 to 2*Pi.
I'm posting this as a solution because this question was the only relevant result in google.
My question/problem was how to add cartesian coordinates inside a circle where x
and y
would not exceed r
.
Examples:
- plot: (45,75) inside a circle with a radius of 100 (this would normally fall inside the circle, but not the correct position)
- plot: (100,100) inside a circle with a radius of 100 (this would normally fall outside the circle
Solution
// The scale of the graph to determine position of plot
// I.E. If the graph visually uses 300px but the values only goto 100
var scale = 100;
// The actual px radius of the circle / width of the graph
var radiusGraph = 300;
// Plot the values on a cartesian plane / graph image
var xCart = xVal * radiusGraph;
var yCart = yVal * radiusGraph;
// Get the absolute values for comparison
var xCartAbs = Math.abs( xCart );
var yCartAbs = Math.abs( yCart );
// Get the radius of the cartesian plot
var radiusCart = Math.sqrt( xCart * xCart + yCart * yCart );
// Compare to decide which value is closer to the limit
// Once we know, calculate the largest possible radius with the graphs limit.
// r^2 = x^2 + y^2
if ( xCartAbs > yCartAbs ) { // Less than 45°
diff = scale / xCartAbs;
radiusMaximum = Math.sqrt( radiusGraph * radiusGraph + Math.pow( yCartAbs * diff, 2) );
} else if ( yCartAbs > xCartAbs ) { // Greater than 45°
diff = scale / yCartAbs;
radiusMaximum = Math.sqrt( radiusGraph * radiusGraph + Math.pow( xCartAbs * diff, 2) );
} else { // 45°
radiusMaximum = Math.sqrt( 2 * ( radiusGraph * radiusGraph ) );
}
// Get the percent of the maximum radius that the cartesian plot is at
var radiusDiff = radiusCart / radiusMaximum;
var radiusAdjusted = radiusGraph * radiusDiff;
// Calculate the angle of the cartesian plot
var theta = Math.atan2( yCart, xCart );
// Get the new x,y plot inside the circle using the adjust radius from above
var xCoord = radiusAdjusted * Math.cos( theta );
var yCoord = radiusAdjusted * Math.sin( theta );
Not sure if this is correct JavaScript code, but something like this:
for (x = -r; x < r; x++) {
for (y = -r; x < r; y++) {
if ((x * x + y * y) < (r * r)) {
// This x/y coordinate is inside the circle.
// Use <= if you want to count points _on_ the circle, too.
}
}
}
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