javascript - How do I iterate over the results of a jQuery selector? - Stack Overflow

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When I'm trying to store all <a> elements as objects in array (using $('a')), and then get the position of each of them, it doesn't work.

years = $('a');
for(i=0;i< years.length;i++){
   if(years[i].position().top > year.position().top){

   }
   else{

   }
}

Console says:

Uncaught TypeError: Object file:///Users/.../index.html# has no method 'position'

When I do it with single element selected by class name instead of tag name, everything works fine.

What am I doing wrong ?

When I'm trying to store all <a> elements as objects in array (using $('a')), and then get the position of each of them, it doesn't work.

years = $('a');
for(i=0;i< years.length;i++){
   if(years[i].position().top > year.position().top){

   }
   else{

   }
}

Console says:

Uncaught TypeError: Object file:///Users/.../index.html# has no method 'position'

When I do it with single element selected by class name instead of tag name, everything works fine.

What am I doing wrong ?

• javascript
• jquery

Share Improve this question Follow edited Aug 2, 2021 at 14:39 isherwood 61.1k1616 gold badges120120 silver badges168168 bronze badges asked May 16, 2012 at 22:08 MichaelMichael 74366 silver badges1818 bronze badges 1

• 3 Should we guess your JavaScript? Or could you possibly help us to help you, by showing what you've tried? – David Thomas Commented May 16, 2012 at 22:10

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2 Answers 2

Sorted by: Reset to default 15

Use this instead:

$("a").each(function() { 
  var pos = $(this).position();
  if (pos.top > year.position().top) {
     // hurray
  }
});

Also what is the value of year? I prefer to name jQuery objects like this: var $year = $("#year"); The $ helps you remember it's a jQuery object.

You can do the following:

var arr = [], elems = $('a');

for(var i = 0; i < elems.length; i++){
   arr[i] = elems[i];
}

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