javascript - Firestore get path of already queried document - Stack Overflow

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I am trying to get the path of a queried document in Firebase Firestore. This is my code:

const location = await db.doc('/locations/US/regions/IOWA').get()
console.log(location.path)

However location.path returns undefined.

location.id works and returns the id.

I have used this as a resource: .firestore.DocumentReference#path

I am trying to get the path of a queried document in Firebase Firestore. This is my code:

const location = await db.doc('/locations/US/regions/IOWA').get()
console.log(location.path)

However location.path returns undefined.

location.id works and returns the id.

I have used this as a resource: https://firebase.google.com/docs/reference/js/firebase.firestore.DocumentReference#path

• javascript
• node.js
• firebase
• google-cloud-firestore

Share Improve this question Follow asked Sep 3, 2019 at 3:43 Leonard NiehausLeonard Niehaus 53066 silver badges1616 bronze badges

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4 Answers 4

Sorted by: Reset to default 11

When you call get() on a DocumentReference, you get back a DocumentSnapshot, which does not have a path property.

You're probably looking for location.ref.path.

The currently accepted answer appears to be outdated, as aDocumentSnapshot does now store the path.

Every DocumentSnapshot has a DocumentReference found under the ref property (https://firebase.google.com/docs/reference/js/v8/firebase.firestore.DocumentSnapshot#ref)

In the DocumentSnapshot, you can then find a string representation of the path under the path property` (https://firebase.google.com/docs/reference/js/v8/firebase.firestore.DocumentReference#path)

In short, you can simply use doc.ref.path to get the path.

The API documentation for DocumentSnapshot says that the reference of the document can be found in its reference property. So you will want to use this: doc.reference.

I know it is old and answered question, this is how I get the document reference from queried document

d.get()
.then(td=>{
   let taskDep = td.data()
   taskDep.id = td.id
   taskDep.ref = td.ref

})

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