javascript - Where should I declare functions that are called inside a useEffect() hook? - Stack Overflow

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So I have the following situation when using a useEffect that calls a functions that depends on state.

Example:

// INSIDE APP COMPONENT

const [someState, setSomeState] = React.useState(0);
const [someTrigger, setSomeTrigger] = React.useState(false);

function someFunction() {
  return someState + 1;  
}

React.useEffect(() => {

  const newState = someFunction();  // 'someFunction' IS BEING CALLED HERE
  setSomeState(newState);

},[someTrigger])

QUESTIONS:

In this case, should I declare someFunction inside the useEffect() or is it safe to keep it outside (but inside component's body)?

I could add it to the dependency array, but it will hurt the redability of my code, since I want to focus on the trigger.

Since the useEffect() will run after a fresh render, is it safe to assume that it will have fresh copies of the functions that I'm calling inside of it?

Is there a basic rule of when you should declare functions inside the useEffect hook or when is it mandatory that you add it to the dependency array?

EDIT: Note that it's necessary that the useEffect has fresh copies of those functions, since those functions need to access some fresh up-to-date state variable.

NOTE:

This code triggers the following eslint warning on CodeSandbox. Although it works just fine.

React Hook React.useEffect has a missing dependency: 'someFunction'. Either include it or remove the dependency array. (react-hooks/exhaustive-deps)eslint

REAL CASE SCENARIO:

This is a simplified example. In my real case, this is a product search page with filters components. So when I click on a filter to activate it (let's say, price <= 50), I'm triggering a useEffect() that is "listening" for the activePriceFilters state variable. That effect then calls a function (someFunction in the example) that will calculate the filteredList and will set the new productList state with the new filteredList.

SNIPPET

function App() {
  
  const [someState, setSomeState] = React.useState(0);
  const [someTrigger, setSomeTrigger] = React.useState(false);
  
  function someFunction() {
    return someState + 1;  
  }
  
  React.useEffect(() => {
  
    const newState = someFunction();
    setSomeState(newState);
  
  },[someTrigger])
  
  return(
    <React.Fragment>
      <div>I am App</div>
      <div>My state: {someState}</div>
      <button onClick={()=>setSomeTrigger((prevState) => !prevState)}>Click</button>
    </React.Fragment>
  );
}

ReactDOM.render(<App/>, document.getElementById('root'));

<script src=".8.3/umd/react.production.min.js"></script>
<script src=".8.3/umd/react-dom.production.min.js"></script>
<div id="root"/>

So I have the following situation when using a useEffect that calls a functions that depends on state.

Example:

// INSIDE APP COMPONENT

const [someState, setSomeState] = React.useState(0);
const [someTrigger, setSomeTrigger] = React.useState(false);

function someFunction() {
  return someState + 1;  
}

React.useEffect(() => {

  const newState = someFunction();  // 'someFunction' IS BEING CALLED HERE
  setSomeState(newState);

},[someTrigger])

QUESTIONS:

In this case, should I declare someFunction inside the useEffect() or is it safe to keep it outside (but inside component's body)?

I could add it to the dependency array, but it will hurt the redability of my code, since I want to focus on the trigger.

Since the useEffect() will run after a fresh render, is it safe to assume that it will have fresh copies of the functions that I'm calling inside of it?

Is there a basic rule of when you should declare functions inside the useEffect hook or when is it mandatory that you add it to the dependency array?

EDIT: Note that it's necessary that the useEffect has fresh copies of those functions, since those functions need to access some fresh up-to-date state variable.

NOTE:

This code triggers the following eslint warning on CodeSandbox. Although it works just fine.

React Hook React.useEffect has a missing dependency: 'someFunction'. Either include it or remove the dependency array. (react-hooks/exhaustive-deps)eslint

REAL CASE SCENARIO:

This is a simplified example. In my real case, this is a product search page with filters components. So when I click on a filter to activate it (let's say, price <= 50), I'm triggering a useEffect() that is "listening" for the activePriceFilters state variable. That effect then calls a function (someFunction in the example) that will calculate the filteredList and will set the new productList state with the new filteredList.

SNIPPET

function App() {
  
  const [someState, setSomeState] = React.useState(0);
  const [someTrigger, setSomeTrigger] = React.useState(false);
  
  function someFunction() {
    return someState + 1;  
  }
  
  React.useEffect(() => {
  
    const newState = someFunction();
    setSomeState(newState);
  
  },[someTrigger])
  
  return(
    <React.Fragment>
      <div>I am App</div>
      <div>My state: {someState}</div>
      <button onClick={()=>setSomeTrigger((prevState) => !prevState)}>Click</button>
    </React.Fragment>
  );
}

ReactDOM.render(<App/>, document.getElementById('root'));

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.8.3/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.8.3/umd/react-dom.production.min.js"></script>
<div id="root"/>

• javascript
• reactjs
• react-hooks
• use-effect

Share Improve this question Follow edited Jul 2, 2019 at 11:42 cbdeveloper asked Jul 2, 2019 at 10:16 cbdevelopercbdeveloper 31.3k4444 gold badges196196 silver badges392392 bronze badges 1

• 1 You can read this FAQ answer. Also, this is an awesome article about useEffect – devserkan Commented Jul 2, 2019 at 10:33

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3 Answers 3

Sorted by: Reset to default 12

A decision to define a function within or outside of useEffect depends on where all the functions is called.

If your function is called only from within the useEffect then it makes sense to define it within the useEffect.

However is the same function is being called from within useEffect as well as other event handlers or other effects, you need to define it outside of useEffect

PS. in your case you are just updating the state for which you needn't define a separate function

function App() {
  
  const [someState, setSomeState] = React.useState(0);
  const [someTrigger, setSomeTrigger] = React.useState(false);
  

  React.useEffect(() => {
    setSomeState(oldState => oldState + 1);
  
  },[someTrigger])
  
  return(
    <React.Fragment>
      <div>I am App</div>
      <div>My state: {someState}</div>
      <button onClick={()=>setSomeTrigger((prevState) => !prevState)}>Click</button>
    </React.Fragment>
  );
}

ReactDOM.render(<App/>, document.getElementById('root'));

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.8.3/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.8.3/umd/react-dom.production.min.js"></script>
<div id="root"/>

As far as you scenario is concerned, you would write it like

useEffect(() => {
    const calcVal = (oldState) => {
         // calculate previous state based on oldState
    }

    setSomeState(calcVal);
}, [activePriceFilters])

Setting another state should not be an effect at all.

 const [someState, setSomeState] = React.useState(0);

 function incrementState() {
    setSomeState(someState => someState + 1);
 }

From performance point of view.

Declaring functions inside the useEffect hook will cause them to be recreated every time the useEffect is triggered.

When you declare a function inside the useEffect hook, it gets redefined each time the component is rendered, as the useEffect hook runs after every render where its dependency array changes. This behavior can lead to unnecessary overhead, particularly if the function doesn't rely on any external variables within the useEffect.

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