validation - Validate 11 Digits in JavaScript - Stack Overflow

admin管理员组

文章数量:1202815

Might be a simple question, but I can't find an answer that fits this bit of code :(

I need to validate a phone number to have EXACTLY 11 digits (no letters)

    function validateForm3() {
  var x=document.forms["booking"]["number"].value;
if (x==null || x=="")
  {
  alert("Please fill in 11 numbers");
  return false;
  }
   var x=document.forms["booking"]["email"].value;
if (x.indexOf("@")=== -1)
  {
  alert("Please enter a valid email");
  return false;
  }
}

I can't really change the structure of this, so it needs to fit into this bit of code :( any suggestions or answers is greatly appeciated :)

Might be a simple question, but I can't find an answer that fits this bit of code :(

I need to validate a phone number to have EXACTLY 11 digits (no letters)

    function validateForm3() {
  var x=document.forms["booking"]["number"].value;
if (x==null || x=="")
  {
  alert("Please fill in 11 numbers");
  return false;
  }
   var x=document.forms["booking"]["email"].value;
if (x.indexOf("@")=== -1)
  {
  alert("Please enter a valid email");
  return false;
  }
}

I can't really change the structure of this, so it needs to fit into this bit of code :( any suggestions or answers is greatly appeciated :)

• javascript
• validation

Share Improve this question Follow edited Feb 8, 2012 at 0:59 phihag 288k7575 gold badges467467 silver badges483483 bronze badges asked Feb 8, 2012 at 0:39 RabianiRabiani 14322 gold badges55 silver badges1212 bronze badges 1

• YOU ARE ALL AMAZING! THANK YOU! – Rabiani Commented Feb 8, 2012 at 0:46

Add a comment  | 

8 Answers 8

Sorted by: Reset to default 13

Use regexp.test:

if (! /^[0-9]{11}$/.test(x)) {
  alert("Please input exactly 11 numbers!");
  return false;
}

Note that you're intentionally excluding a lot of phone numbers, including international ones or alternative writing styles of phone numbers you could reach. You should really just test for /^\+?[0-9]+$/.

if (!/^\d{11}$/.test(x)) 
    alert('These are not 11 digits!');
else 
    alert('Passed!');

Try it http://jsfiddle.net/LKAPN/1/

Use regex:

"1234".match(/^\d{4}$/);

Explanation:

^   - matches the beginning of the string
\d  - matches one digit
{4} - tells that we want four digits (you want thirteen then)
$   - matches the end of the string

See https://developer.mozilla.org/en/JavaScript/Guide/Regular_Expressions for further reading.

You can use regex for that:

var str = '12345678900';
if (str.match(/^\d{11}$/)) {
    // Valid
}

Maybe something like:

if (x.length == 11 && +x == x)

kinda hacky, but you could do:

if(x.length==11)
{
    for (var i=0; i<x.length; i++)
    {
        if (parseInt(x[i])!=x[i])
        {
            alert("only enter numbers!");
        }
    }
}
else
{
    alert("must enter 11 digits!");
}

You can the use regular expression:

\d{11}

However, you probably also want to strip whitespace:

var isElevenNumbers = (/^\d{11}$/m.test(mynumber.replace(/\s]/g, '')));

And you may want to strip more for internation numbers, e.g. +1-234-567-9090

var isElevenNumbers = (/^\d{11}$/m.test(mynumber.replace(/[\s\+\-]/g, '')));

where 'mynumber' is your variable holding the value.

Steven Levithan has a very useful excerpt on Regexps that validate North American as well as international phone numbers at http://blog.stevenlevithan.com/archives/validate-phone-number .

That page is excerpted from his book Regular Expressions Cookbook (O'Reilly, 2009)

本文标签： validationValidate 11 Digits in JavaScriptStack Overflow