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I was trying to convert date object into long format (may be in milliseconds format) as we do in java.
So to fulfill my need, after some trial and error, I found below way which works for me:
var date = new Date();
var longFormat = date*1; // dont know what it does internally
console.log(longFormat); // output was 1380625095292
To verify, I reverse it using new Date(longFormat);
and it gave me correct output. In short I was able to fulfill my need some how, but I am still blank what multiplication does internally ? When I tried to multiply current date with digit 2, it gave me some date of year 2057 !! does anyone know, what exactly happening ?
I was trying to convert date object into long format (may be in milliseconds format) as we do in java.
So to fulfill my need, after some trial and error, I found below way which works for me:
var date = new Date();
var longFormat = date*1; // dont know what it does internally
console.log(longFormat); // output was 1380625095292
To verify, I reverse it using new Date(longFormat);
and it gave me correct output. In short I was able to fulfill my need some how, but I am still blank what multiplication does internally ? When I tried to multiply current date with digit 2, it gave me some date of year 2057 !! does anyone know, what exactly happening ?
6 Answers
Reset to default 12The long format displays the number of ticks after 01.01.1970, so for now its about 43 years.
*
operator forces argument to be cast to number, I suppose, Date
object has such casting probably with getTime()
.
You double the number of milliseconds - you get 43 more years, hence the 2057 (or so) year.
What you are getting when you multiply, is ticks
Visit: How to convert JavaScript date object into ticks
Also, when you * 2
it, you get the double value of ticks, so the date is of future
var date = new Date()
var ticks = date.getTime()
ref: Javascript Date Ticks
getTime
returns the number of milliseconds since January 1, 1970. So when you * 1
it, you might have got value of this milliseconds. When you * 2
it, those milliseconds are doubled, and you get date of 2057!!
Javascript date objects are based on a UTC time value that is milliseconds since 1 January 1970. It just so happens that Java uses the same epoch but the time value is seconds.
To get the time value, the getTime method can be used, or a mathematic operation can be applied to the date object, e.g.
var d = new Date();
alert(d.getTime()); // shows time value
alert(+d); // shows time value
The Date constructor also accepts a time value as an argument to create a date object, so to copy a date object you can do:
var d2 = new Date(+d);
If you do:
var d3 = new Date(2 * d);
you are effectively creating a date that is (very roughly):
1970 + (2013 - 1970) * 2 = 2056
Dates are internally stored as a timestamp, which is a long-object (more info on timestamps). This is why you can create Dates with new Date(long). If you try to multiply a Date with an integer, this is what happens:
var date = new Date();
var longFormat = date*1;
// date*1 => date.getTime() * 1
console.log(longFormat); // output is 1380.....
Javascript tries to find the easiest conversion from date to a format that can be multiplied with the factor 1, which is in this case the internal long format
Just use a date object methods.
Read the docs: JavaScript Date object
var miliseconds=yourDateObject.getMiliseconds();
If You want to get ticks:
var ticks = ((yourDateObject.getTime() * 10000) + 621355968000000000);
or
var ticks = someDate.getTime();
You could try the parsing functionality of the Date constructor, whose result you then can stringify:
>
new Date("04/06/13").toString()
"Sun Apr 06 1913 00:00:00 GMT+0200"
// or something But the parsing is implementation-dependent, and there won't be many engines that interpret your odd DD/MM/YY format correctly. If you had used MM/DD/YYYY, it probably would be recognized everywhere.
Instead, you want to ensure how it is parsed, so have to do it yourself and feed the single parts into the constructor:
var parts = "04/06/13".split("/"),
date = new Date(+parts[2]+2000, parts[1]-1, +parts[0]);
console.log(date.toString()); // Tue Jun 04 2013 00:00:00 GMT+0200
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date.getTime()
) – devnull69 Commented Oct 1, 2013 at 11:11