regex - javascript check if value has at least 2 or more words - Stack Overflow

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I have a field that you enter your name in and submit it. I would like the receive peoples first and last names and to do this i need to check if the value contains at least 2 words. This is what I am using right now but it doesn't seem to work.

function validateNameNumber(name) {
    var NAME = name.value;
    var matches = NAME.match(/\b[^\d\s]+\b/g);
    if (matches && matches.length >= 2) {
        //two or more words
        return true;
    } else {
        //not enough words
        return false;
    }
}

I have a field that you enter your name in and submit it. I would like the receive peoples first and last names and to do this i need to check if the value contains at least 2 words. This is what I am using right now but it doesn't seem to work.

function validateNameNumber(name) {
    var NAME = name.value;
    var matches = NAME.match(/\b[^\d\s]+\b/g);
    if (matches && matches.length >= 2) {
        //two or more words
        return true;
    } else {
        //not enough words
        return false;
    }
}

• javascript
• regex
• string
• input

Share Improve this question Follow edited Aug 16, 2014 at 22:37 Jeremy J Starcher 23.9k66 gold badges5555 silver badges7575 bronze badges asked Aug 16, 2014 at 22:32 Bryce HahnBryce Hahn 1,77355 gold badges1818 silver badges2626 bronze badges 9

• 1 What does "doesn't seem to work" mean? Show your input and explain both the expected and observed output. Your code works for me. – cookie monster Commented Aug 16, 2014 at 22:38
• 4 @lvogel: He's not, I am because they're really bad answers. – cookie monster Commented Aug 16, 2014 at 22:44
• 2 @cookiemonster So provide an answer on yourself. – lvogel Commented Aug 16, 2014 at 22:45
• 1 @lvogel: No, not until the OP has answered my question above. – cookie monster Commented Aug 16, 2014 at 22:46
• 1 You should probably be looking for groupings of the characters you do want instead of those that you don't want. For example, /\w+/g – cookie monster Commented Aug 16, 2014 at 22:55

 |  Show 4 more comments

6 Answers 6

Sorted by: Reset to default 24

str.trim().indexOf(' ') != -1 //there is at least one space, excluding leading and training spaces

The easy solution (not 100% reliable, since "foo   " returns 4, as @cookiemonster mentioned):

var str = "Big Brother";
if (str.split(" ").length > 1) {
    // at least 2 strings
}

The better solution:

var str = "Big Brother";
var regexp = /[a-zA-Z]+\s+[a-zA-Z]+/g;
if (regexp.test(str)) {
    // at least 2 words consisting of letters
}

You could use the String.Split() method:

function validateNameNumber(name) {
    var NAME = name.value;
    var values = name.split(' ').filter(function(v){return v!==''});
    if (values.length > 1) {
        //two or more words
        return true;
    } else {
        //not enough words
        return false;
    }
}

If you were to pass "John Doe" as the name value, values would equal {"john", "doe"}

http://www.w3schools.com/jsref/jsref_split.asp

Edit: Added filter to remove empty values. Source: remove an empty string from array of strings - JQuery

Probably not the best solution overall (see the other answers), but one that shows how to count the number of times a regexp matches a string:

function validateNameNumber(name) {
    var nameValue = name.value;
    var regexp = /\b[^\d\s]+\b/g;
    var count = 0;
    while (regexp.exec(nameValue)) ++count;
    if (count >= 2) {
        //two or more words
        return true;
    } else {
        //not enough words
        return false;
    }
}

Change this line from your snippet

var matches = NAME.match(/\b[^\d\s]+\b/g);

to this

var matches = NAME.match(/\S+/g);

or to this, if numbers should be excluded

var matches = NAME.match(/\b([a-z]+)\b/gi);

Side (funny) note: Your snippet works just fine. Check the jsBin

I would just check for whitespace by running a for loop.

var correctFormat = false;
for (var i = 0; i = i < name.length; i++) {
    if (name[i] === " ") {
       correctFormat = true;
    }
}
if (correctFormat === false) {
    alert("You entered an invalid name");
    return false;
} else {
    return true;
}

If the name doesn't have a space, knowing that there is a space between the first and last name, it would alert("You entered an invalid name");

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