javascript - ES6 Object Destructuring Default Parameters - Stack Overflow

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I'm trying to figure out if there's a way to use object destructuring of default parameters without worrying about the object being partially defined. Consider the following:

(function test({a, b} = {a: "foo", b: "bar"}) {
  console.log(a + " " + b);
})();

I'm trying to figure out if there's a way to use object destructuring of default parameters without worrying about the object being partially defined. Consider the following:

(function test({a, b} = {a: "foo", b: "bar"}) {
  console.log(a + " " + b);
})();

When I call this with {a: "qux"}, for instance, I see qux undefined in the console when what I really want is qux bar. Is there a way to achieve this without manually checking all the object's properties?

• javascript
• ecmascript-6

Share Improve this question Follow edited Jul 6, 2016 at 7:16 Quentin Roy 7,87722 gold badges3333 silver badges5252 bronze badges asked Oct 26, 2014 at 21:27 user3019273user3019273 1,43322 gold badges99 silver badges44 bronze badges

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1 Answer 1

Sorted by: Reset to default 263

Yes. You can use "defaults" in destructuring as well:

(function test({a = "foo", b = "bar"} = {}) {
  console.log(a + " " + b);
})();

This is not restricted to function parameters, but works in every destructuring expression.

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